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@ali1029 @hubbabubba can you help me?
Are you wanting to graph the function?
no im just wanting to know the real world application and a example
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Model the data in the chart with a linear function, find the slope, then you can choose one of the two points and write an equation in point-slope form, or you could plug in one point and the slope into slope-intercept form (y = mx+b) and solve for the y-intercept
thanks @ali1029 but also can you give me a real world application?
like any example?
alright hold on
The chart shows a country’s annual egg production. Model the data in the chart with a linear function, using the points (2, 57.7) and (4, 61.3) Predict egg production in 2008. Here is the chart:
Year, x Egg Production (in billions), y
1994, 0 55.4
1995, 1 56.2
1996, 2 57.7
1997, 3 59.2
1998, 4 61.3
1999, 5 63.8
200, 6 65.7
So, you would model the data in the chart with a linear function, using the points (2, 57.7) and (4, 61.3), find the slope:
change in y over change in x = 3.6 / 2 = 1.8 . point-slope form:
y - y1 = m(x - x1)
y - 57.7 = 1.8(x - 2)
y - 57.7 = 1.8x - 3.6
y = 1.8x + 54.1
Second, find the production in 2008. That's year 14 (2008 - 1994), so plug 14 in for x, so you can calculate y.
Answer: y = 1.8x + 54.1
y = 1.8(14) + 54.1
y = 79.3 billion eggs in 2008