anonymous
  • anonymous
verify the trig equation by sub identities to match the right side cot x sec^4x=cot x + 2 tan x + tan^3x
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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Luigi0210
  • Luigi0210
Did you try it?
anonymous
  • anonymous
yea Im just so lost with this hsit because everyone is dofferent
anonymous
  • anonymous
like its saying ignore the right side and make the left side equal to the right

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anonymous
  • anonymous
and I have my identities
DebbieG
  • DebbieG
Kind of, yes... :) this isn't "solving an equation" which is what you are used to. This is "prove the identity", so the goal is to show - using algebra and trig identities that you arleady have - that the expression on the left is equivalent to the one on the right. So you need to work FROM one side, TO the other, and show step by step what gets you there.
anonymous
  • anonymous
ok its saying work the left side to show its equal to the right
DebbieG
  • DebbieG
\(\Large \cot x \sec^4x=\cot x + 2 \tan x + \tan^3x\) OK, I notice that there is a product on the left and I need to get to a sum on the right. The sum on the right has a cotx in it, just like I start with on the left. But it has all that tangent stuff too, right?
anonymous
  • anonymous
ok I see what you mean
anonymous
  • anonymous
can we just cancel them?
DebbieG
  • DebbieG
So I need to get rid of sec^4, and get me some tangents. Can you think of an identity that relates secant and tangent? And btw, I see that it seems to imply go left -> right... I find that kind of silly. As long as you go FROM one side TO the other, you can start on whichever you want. You can always reverse what you did to show it from either side.
DebbieG
  • DebbieG
NO, there is no "cancelling"... remember, NOT an equation. We are going FROM one side TO the other. We want to start on the left, and find algebraic steps to show: \(\Large \cot x \sec^4x=.......\\ \Large ..................=\\ \Large ..................=\\ \Large ..................=\\ \Large \cot x + 2 \tan x + \tan^3x\) Just need to fill in the steps!
anonymous
  • anonymous
is it one of the pythagreom identities?
DebbieG
  • DebbieG
yes, that's what i'm thinking....
RadEn
  • RadEn
i already solved this question last one month ago :) http://openstudy.com/study#/updates/51effc9be4b0c8f6bc34712d
anonymous
  • anonymous
1+tan^2u=sec^2u
anonymous
  • anonymous
ok now this is were I get really confused like what the heck am I supposed to do with that long thing
DebbieG
  • DebbieG
right... go check out @RadEn 's link, that's pretty much where I was going with it. But try it yourself first!
anonymous
  • anonymous
kinda confused at that if you don't mind can we take it step by step because I have like 4 more I have to do after this
anonymous
  • anonymous
and they don't get easier
DebbieG
  • DebbieG
ok, you have: \(\Large \cot x \sec^4x\) Now, \(\Large \sec^4x=(sec^2x)^2\) right?
anonymous
  • anonymous
ok where did the exponent of 2 come from on the right side I see the sec^2x is part of the identity
DebbieG
  • DebbieG
hang on, phone...
DebbieG
  • DebbieG
so sorry, I have to go....
anonymous
  • anonymous
ok thanks fir trying

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