anonymous
  • anonymous
GUYS PLS. HELP. find the equation of ellipse. center @origin. focus at (- square root 13, 0) vertex at (0,2).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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ybarrap
  • ybarrap
With focus at \((-\sqrt {13},0)\) and a vertex at \((0,2)\), we have the following situation:|dw:1378771036897:dw| Equation of an ellipse is \(\large {x^2 \over a^2}+{y^2\over a^2-f^2}=1\), where a=half the major axis (horizontal) and f is the focus. We are given that b, half the minor axis is 2. Focus: \(f=\sqrt{a^2-b^2}\), from which we can get a. We now have everything we need to solve this problem. Does this make sense?
anonymous
  • anonymous
yes yes thank you :)))
ybarrap
  • ybarrap
your welcome

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anonymous
  • anonymous
@ybarrap how did you come up with 9 (in the graph) ? i mean, square root of 13 equal to 3.60.. hehe
ybarrap
  • ybarrap
In the graph, it's actually an "a" not a "9". That's the x-coordinate of the vertex for one on the the major axis of the ellipse, (a,0).
ybarrap
  • ybarrap
the sqrt of 13 is the focus and is not on the vertex, but located a short distance before it.
ybarrap
  • ybarrap
does this make any sense, i know my sketching is terrible
anonymous
  • anonymous
sorry hahaha. yes thank you again ;)
ybarrap
  • ybarrap
not a problem

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