anonymous
  • anonymous
A particle undergoes two displacements, measured from the positive x -axis, with counter-clockwise positive. The first has a magnitude of 11 m and makes an angle of 67◦ with the positive x axis. The resultant displacement has a magnitude of 73 m directed at an angle of 105degrees from the positive x-axis. Find the Magnitude and angleof the 2nd displacement
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
I found the magnitude. I am trying to interpret the angle
anonymous
  • anonymous
\[\theta=\tan^{-1} (\frac{ -3.07 }{ -6.19 })=26.421\]
anonymous
  • anonymous
since this Bx<0 and By<0 I assume this is in the 3rd quad, thus would I just do 26.421-180 to find the angle??

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
@ganeshie8 can you help possibly?
anonymous
  • anonymous
THanks for coming :)
jim_thompson5910
  • jim_thompson5910
hmm this is certainly a tough one, but it's doable
anonymous
  • anonymous
I have solved the majority of it, just trying to do the trig part of it
jim_thompson5910
  • jim_thompson5910
did you draw out a parallelogram?
anonymous
  • anonymous
no, I just used the laws of sines and cosines
anonymous
  • anonymous
for the magnitude
anonymous
  • anonymous
if both x and y are negative it is in the 3rd quad?
jim_thompson5910
  • jim_thompson5910
where does it say they're negative?
anonymous
  • anonymous
i figured that out in part 1 finding the magnitude. deltax -6.19 and deltay is -3.07
jim_thompson5910
  • jim_thompson5910
ok one sec
anonymous
  • anonymous
Rcos(r)-Acos(a) = Bx Rsin(r)-Asin(a) = By thus b = sqrt(by^2+bx^2)
anonymous
  • anonymous
my issue is the angle.. is it negative? do i need to add or subtract to the value I got from arctan(deltay/deltax) ?
jim_thompson5910
  • jim_thompson5910
drawing it out, one sec
anonymous
  • anonymous
awesome, thanks
anonymous
  • anonymous
just curious, why a parallelogram? I drew it myself and now I can see thats its a negative angle (I had part of it drawn out earlier)
jim_thompson5910
  • jim_thompson5910
you draw a parallelogram because the two initial vectors (ie forces) pull and create a resultant vector which is really the diagonal of the parallelogram so you need a parallelogram to figure out the magnitude of the diagonal and the angle of the diagonal
jim_thompson5910
  • jim_thompson5910
so it's like this |dw:1378771093709:dw|
jim_thompson5910
  • jim_thompson5910
use the parallelogram law |dw:1378771136642:dw|
jim_thompson5910
  • jim_thompson5910
resultant is this diagonal here |dw:1378771170948:dw|
anonymous
  • anonymous
ahh very nice explanation!
anonymous
  • anonymous
that is the best physics explanation ive heard in 3 weeks of lecture :)
anonymous
  • anonymous
theta = -153.58
jim_thompson5910
  • jim_thompson5910
lol I'm glad to hear that
jim_thompson5910
  • jim_thompson5910
atm I'm trying to accurately draw it so I can have it to check
anonymous
  • anonymous
Thank you Jim. I entered it on the utexas physics website and it accepted the angle.
jim_thompson5910
  • jim_thompson5910
oh you figured it all out?
anonymous
  • anonymous
yep :)
jim_thompson5910
  • jim_thompson5910
ok that's great
anonymous
  • anonymous
I was almost there.. but every answer u answer wrong they mark you points off... so i was making triple sure.. and ur explanation sealed the deal
jim_thompson5910
  • jim_thompson5910
I'm glad it did

Looking for something else?

Not the answer you are looking for? Search for more explanations.