anonymous
  • anonymous
tanθ (see attachment)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
|dw:1378771355448:dw|
jim_thompson5910
  • jim_thompson5910
hint: use the unit circle and the idea that tan(x) = sin(x)/cos(x)
anonymous
  • anonymous
Can you do this problem with me to see if I can understand the next ones? @jim_thompson5910

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jim_thompson5910
  • jim_thompson5910
do you have the unit circle with you?
anonymous
  • anonymous
Yes
jim_thompson5910
  • jim_thompson5910
ok what is sin(60)
anonymous
  • anonymous
-0.3048106211
jim_thompson5910
  • jim_thompson5910
don't use a calculator
jim_thompson5910
  • jim_thompson5910
use the unit circle
anonymous
  • anonymous
Oh. \[\frac{ \sqrt{3} }{ 2 } \]
jim_thompson5910
  • jim_thompson5910
good
jim_thompson5910
  • jim_thompson5910
it's \[\frac{ \sqrt{3} }{ 2 } \]
jim_thompson5910
  • jim_thompson5910
what is cos(60)
anonymous
  • anonymous
1/2
jim_thompson5910
  • jim_thompson5910
divide sin(60) by cos(60) to get your answer
anonymous
  • anonymous
\[\sqrt-{3}\]
anonymous
  • anonymous
Well - on the outside
jim_thompson5910
  • jim_thompson5910
no it's positive, so the answer is actually \[\large \sqrt{3}\]
jim_thompson5910
  • jim_thompson5910
hopefully you see how it's positive?
anonymous
  • anonymous
Yes, thank you!
anonymous
  • anonymous
How would I find sin of 225?
anonymous
  • anonymous
@jim_thompson5910
jim_thompson5910
  • jim_thompson5910
225 is also found on the unit circle
jim_thompson5910
  • jim_thompson5910
do you see it?
anonymous
  • anonymous
Yes. What is the ratio for sin and cos I mean?
jim_thompson5910
  • jim_thompson5910
don't worry about cos, just focus on sine
anonymous
  • anonymous
I understand how to solve them, I just need the ratios now :)
jim_thompson5910
  • jim_thompson5910
check out this unit circle and look for the angle 225 degrees http://www.regentsprep.org/regents/math/algtrig/ATT5/600px-Unit_circle_angles_svg.jpg
anonymous
  • anonymous
I understand all that.. Tan = sin/cos .... What is that ratio for sin and cos? I have other problems to do.
jim_thompson5910
  • jim_thompson5910
there is no ratio for sine and cosine, oh you mean like sine = opposite/hypotenuse and cosine = adjacent/hypotenuse
anonymous
  • anonymous
Yes, thank you!
jim_thompson5910
  • jim_thompson5910
ok glad it's clicking
anonymous
  • anonymous
So the sin for 225 would just be - sqrt 2 over 2 right?
jim_thompson5910
  • jim_thompson5910
good

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