anonymous
  • anonymous
lim of 2-|x|/2+x as you approach -2
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
For \(x<0\) (that includes \(x=-2\)), you have \(|x|=-x\). \[\lim_{x\to-2}\frac{2-|x|}{2+x}=\lim_{x\to-2}\frac{2-(-x)}{2+x}\]
anonymous
  • anonymous
isnt there more to it as well?
anonymous
  • anonymous
Simplify it. \(2-(-x)=2+x\), so you have \(\dfrac{2+x}{2+x}=\cdots\).

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anonymous
  • anonymous
its one but since its a absolute value problem dont you have to evaluate it from both sides?
anonymous
  • anonymous
No. The function is perfectly continuous for all values of \(x\) other than -2. The limit takes advantage of this fact; we're only *approaching* 2, and not actually *touching* it.

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