anonymous
  • anonymous
Which of the following use of cases covers all possibilities when there are two real variables x and y, and the domain is R? Case 1: x > 0 and y > 0 Case 2: x < 0 and y < 0 Case 3: x = 0 and y = 0 Case 1: x not 0 Case 2: y not 0 Case 3: x = 0 and y = 0 Case 1: x not 0 and y not 0 Case 2: x = 0 and y = 0 Case 1: x = 0 Case 2: y = 0 case 3: x not zero and y not 0
Mathematics
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SOLVED
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chestercat
  • chestercat
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Psymon
  • Psymon
Im guessing the R is to represent all real numbers, right?
anonymous
  • anonymous
Yes.. R is the notation of real number
anonymous
  • anonymous
what's your opinion regarding all the choices? For myself, it is either the second or the fourth one

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Psymon
  • Psymon
Can you tell me why you think that?
anonymous
  • anonymous
when x = 0, it means y equals 0 or y not equal 0. when y = 0, it means x equal 0 or x not equals 0.then x not equals 0 and y not equals 0. it covers all the possibilities
anonymous
  • anonymous
the first and the third are incomplete. the first one should include x<0 and y>0 & x >0 and y<0
anonymous
  • anonymous
the third should have x not 0 but y = 0, y not 0 but x = 0
Psymon
  • Psymon
Oh, I was misinterpreting the problem. When you put up the cases, I was grouping them together how you wrote them, not matching all the case 1's together.
anonymous
  • anonymous
I see. which one do you think it covers all the possibilities of cases?
Psymon
  • Psymon
Yeah, just awkward how its written. So I have 3 cases to choose from? O.o Because "Case 1: x > 0 and y > 0 Case 2: x < 0 and y < 0 Case 3: x = 0 and y = 0" Looks complete, but not sure if this is an option or if its just a mix of the 3 cases.
anonymous
  • anonymous
altogether this is just a choice. Let me post the question again.
anonymous
  • anonymous
Which of the following use of cases covers all possibilities when there are two real variables x and y, and the domain is R? (A) Case 1: x > 0 and y > 0 Case 2: x < 0 and y < 0 Case 3: x = 0 and y = 0 (B) Case 1: x not 0 Case 2: y not 0 Case 3: x = 0 and y = 0 (C) Case 1: x not 0 and y not 0 Case 2: x = 0 and y = 0 (D)Case 1: x = 0 Case 2: y = 0 case 3: x not zero and y not 0
Psymon
  • Psymon
Then A looks like itd be it to me. The other 3 are too ambiguous.
anonymous
  • anonymous
But for A, it is lack of two more cases. x<0 and y>0 & x >0 and y<0 . x,y are real numbers
Psymon
  • Psymon
See, thats where Im getting confused with the set-up. Under A it has x and y > 0 O.o
anonymous
  • anonymous
yup
Psymon
  • Psymon
Yeah, since A covers (A) Case 1: x > 0 and y > 0 Case 2: x < 0 and y < 0 Case 3: x = 0 and y = 0 Those are all the cases. Or do I need to be looking at it like: Case 1: x >0 Case 1: x not 0 Case 1: x not 0 and y not 0 Case 1: x = 0 ?
anonymous
  • anonymous
Case 1: x > 0 and y > 0 Case 2: x < 0 and y < 0 Case 3: x = 0 and y = 0 Doesn't allow \((-1,1)\)
anonymous
  • anonymous
Case 1: x not 0 and y not 0 Case 2: x = 0 and y = 0 Doesn't allow \((1,0)\)
anonymous
  • anonymous
Yup. You are right. so which is the correct one?

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