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ineedyouubiebs
 one year ago
What's a formula to uncover a way to divide a line segment into three equal parts. What would the formula look like?
ineedyouubiebs
 one year ago
What's a formula to uncover a way to divide a line segment into three equal parts. What would the formula look like?

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ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0@some_someone ?

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0@Luigi0210 lol sorry to bother you! /.\

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0Any clues at all?

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0oh its fine I can try asking someone else:)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1do you mean find the length of each piece? or actually trisect the segment through a geometric construction?

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0I think to find the length of each piece. The exact questions says: Now that you know how to find the midpoint from two endpoints, tweak your understanding of the formula to uncover a way to divide a line segment in to three equal parts. What would the formula look like?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1One way to do it is to divide the horizontal component of the length by 3 this will give you how far to space the points out in a horizontal sense you must do the same for the vertical component as well

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so say you had this segment dw:1378786046754:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1draw in the horizontal and vertical components dw:1378786083004:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1then cut those lengths into 3 congruent pieces dw:1378786121773:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1then use these cuts to figure out where the 1/3 and 2/3 markers go on the original line segment dw:1378786176000:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1dw:1378786217033:dw

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0yeah, i get what your saying, but there isn't any specific formula where you have to plug in the numbers?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1well this distance here dw:1378786360035:dw is the difference in the x coordinates

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1this distance is the difference in the y coordinates dw:1378786383951:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so you're subtracting the coordinates, then dividing by 3 to get those markers on the horizontal/vertical components and you're using those markers to get the 1/3 and 2/3 markers

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0but the question is asking me for a formula?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1I know, I'm trying to get you to think of what that formula would be based on what I'm giving you

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0how about a+b+c=? divide by 3

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1remember you're taking the differences in the corresponding coordinates, then dividing by 3

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0oh so then instead of adding them, im subtracting them?

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1let m = x2  x1 this is the horizontal component length and let n = y2  y1 this is the vertical component length

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1cut these distances into 3rds: m > m/3 n > n/3 so if you have the segment with the endpoints (x1,y1) and (x2,y2), then you're adding on m/3 to the coordinates to get these points 1/3 marker: (x1 + 1*m/3, y1 + 1*n/3) 2/3 marker: (x1 + 2*m/3, y1 + 2*n/3) you could avoid using m and n and just use the distances above, but that notation gets even uglier

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0yeah, this looks really complicated lol:p

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1it's not too bad once you get used to it

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0thanks for helping me tough. i hope the teacher goes over this tommorow because right now i just want to know out!

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1do you see how I defined m and n?

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0Yeah, yes I did:)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so if you cut m into 3 then you basically get this distance here dw:1378787464289:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1and if you divide n by 3, you get this length here dw:1378787503944:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1with me so far?

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0yes, with you so far:)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1so that's why if you start with (x1,y1) dw:1378787643610:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1and you move m/3 units along the x axis and n/3 units along the y axis, then you'll land at the 1/3 marker dw:1378787687368:dw

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1that explains why the coordinate of the 1/3 marker is (x1 + m/3, y1 + n/3) and you can write it as (x1 + 1*m/3, y1 + 1*n/3)

ineedyouubiebs
 one year ago
Best ResponseYou've already chosen the best response.0thank you so much i appreciate it:)

jim_thompson5910
 one year ago
Best ResponseYou've already chosen the best response.1you're welcome, the 2/3 mark is found in much the same way, you add on another m/3 to the x coordinate and another n/3 to the y coordinate to get 2/3 marker: (x1 + m/3+m/3, y1 + n/3+n/3) which turns into 2/3 marker: (x1 + 2*m/3, y1 + 2*n/3)

dan815
 one year ago
Best ResponseYou've already chosen the best response.0jims way is the nicest way though
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