anonymous
  • anonymous
Trig questions- sin, cos, tan
Mathematics
  • Stacey Warren - Expert brainly.com
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
@jim_thompson5910 can you help me out?
anonymous
  • anonymous
@RadEn

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anonymous
  • anonymous
pi/4 obviously since that is listed as the answer then the (sqrt2/2, sqrt2/2) would repeat at angle 3pi/4 but since it is in the 2nd quadrant the cos part would be negative so that won't work then (sqrt2/2, sqrt2/2) comes up again at 5pi/4 -- this time quadrant 3 both the cos and sine part are negative....that should look like a pattern
anonymous
  • anonymous
so you're saying the answer is pi/4 but not the other 2 @kantalope
anonymous
  • anonymous
well part of what I'm saying now is that I didn't read the question very well sorry.... it is looking just for the sin part being positive, yes? Positive sin is in Q1 and Q2...so that part where I say that won't work....really it does
anonymous
  • anonymous
If you google images "unit circle" you can see some that are all filled in and see how the pattern works
anonymous
  • anonymous
@.Sam. help?
anonymous
  • anonymous
pi/4 = (sqrt2/2, sqrt2/2) 3pi/4 = (-sqrt2/2, sqrt2/2) 5pi/4 = (-sqrt2/2, -sqrt2/2) 7pi/4 = (sqrt2/2, -sqrt2/2) t sin is the y component and second point each bracket set up as (x,y) so sin is positive sqrt2/2 at pi/4 and 3pi/4
anonymous
  • anonymous
thanks for the help...i learned this a couple months back and im trying to refresh the material.

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