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This is a pretty simple derivative trick, to check if you have the right answer.
Let's say we have this equation: |dw:1378797236769:dw|
To get the derivative, all we do is "drop" the power, like so: |dw:1378797288603:dw| Then subtract one
When dropping a power, you multiply it by whatever number is infront of that variable: the x^2 had a 1 in it, so 2*1=2 making it 2x The 3x had a power of 1, so drop that, 3*1=3. Since the x just had a power of 1, and we subtract 1, that makes it x^0, and anything(almost) to the 0 is one. So 3*1*1, making it just 3 Making sense so far?
And the derivative of any constant, K, is always zero.
So the derivative of let's say, 3, is 0.
And let's solve that equation using the quotient rule: |dw:1378797614161:dw| |dw:1378797766826:dw| We get the same thing.
|dw:1378797961866:dw| This is what I'm having a road block understanding.
Sorry I meant difference quotient, not quotient rule. You'll get to Quotient rule in calc :3
All that comes from This: |dw:1378798135442:dw| The first part is this: \[f(x+h)\] meaning for your function, where ever there is a variable, plug in an (x+h)
and the x just happened to be squared, so the (x+h) replaces the x in that spot
Oh, okay. And the f just takes a coffee break?
Yea, it's just there to signify function
Got it :) Thank you
I hope so >.<
Good luck tomorrow!