At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
(x-8)(x-8) = x ^2 -8x+ (-8x) (-)-8^2 = x^2 - 16x + 64
is that what you need to do O. o?
yeah, i did it again and got that but i didnt know if it was right.. thanks heaps
:D you are welcome~
i have another question. Do you know how to do parabolas??
um, i will try :D
ok, because i keep doing something wrong and i was just wondering if you could do the equation so i could see where i went wrong.. if thats not asking too much??
yeah, sure, i will do my best XD
ok, thanks. heres the question..
Over a period of 8hours, the temperature of a room follows the relationship T=h^2-6h+15 where T is the temperature in degrees Celcius, h hours after commencing the experiment a) Sketch the graph of this quadratic relationship b) What is the initial temperature? c) After 2 hours, is the temperature of the room increasing or decreasing? d) After 6 hours is the temperature of the room increasing or decreasing? e) Find the minimum temperature f) When did the minimum temperature occur? Sorry, it's alot :(
a) y intercept : h=0 T=y y= 0^2 - 6(0) + 15 = 15 |dw:1378810220040:dw| i think the initial temperature will be the y intercept (0, 15) for the hours(x/ h)can not be negative c) T = (2)^2 - 6(2) + 15 (sub in or look at the graph) = 4 - 12 +15 = 7 (which mean decrease) d) same sub in or look at the graph T = (6)^2 - 6(6) + 15 = 36 - 36 + 15 = 15 (which mean it stay the same ( so it goes decrease at h = 7 and slowly go back up and h=6 will be back to the start temperature ) e) the minimum is the turning point which is T = x^2 - 6h + 15 = (x^2-6x+9) + 6 = (x - 3)^2 + 6 TP: (3, 6)
|dw:1378811359696:dw| Oh... drawing a graph here is so hard T ^ T
haha, OMG... YOU'RE A LIFESAVER..
> " < thanks~~ it make sense right? (i am not really good at explaining...)
yeah, im sure i will be able to understand it somehow... are you in school??
oh, and e and f is basally asking for the turning point e) 6 f) 3 yes, i am still learning XD have a test tomorrow
oh no, sorry.. i am probably confusing you.. do you live in Australia?
i am happy to help~~ :D so no worries, how can you know that i am from Aus O . O
no, im just guessing cause thats where im from.. :P what subject do you have a test on?
i have test on circular functions T ^ T
that sounds not one bit interesting to me. my maths exam is on friday the 13th, how unlucky
oh! good luck :P
thanks, you too :)
thanks :D i will go back to study now, study well!!
yeah, sorry about bothering you. Thanks, you too!!
no need to say sorry, i am glad that i help