anonymous
  • anonymous
Given the equation radical 8x+1 = 5, solve for x and identify if it is an extraneous solution. a. x = 1/4 , solution is not extraneous b. x =1/4 , solution is extraneous c. x = 3, solution is not extraneous d. x = 3, solution is extraneous
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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yamyam70
  • yamyam70
you mean \[\sqrt{8x +1}\] = 5 ?
anonymous
  • anonymous
Is it the question ? \[sqrt{8x+1}\]=5 Please answer and get answer :)
anonymous
  • anonymous
@yamyam70 yes

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More answers

yamyam70
  • yamyam70
hello, if a linear equation has a radical , square both sides :)
anonymous
  • anonymous
so it would be 64x+1=25
yamyam70
  • yamyam70
\[(\sqrt{8x + 1} )^2 = (5)^2\]
yamyam70
  • yamyam70
nope, by squaring both sides, take notice of the left hand side, we remove the radical.
yamyam70
  • yamyam70
\[\sqrt{8x + 1 } \times \sqrt{8x +1} = 8x +1 \]
anonymous
  • anonymous
so the left side would stay 8x+1
yamyam70
  • yamyam70
aha!
yamyam70
  • yamyam70
so please continue, 8x + 1 = (5)^2 :)
anonymous
  • anonymous
x=3?
yamyam70
  • yamyam70
How did you get that answer? :)
anonymous
  • anonymous
subtract 1 from each side then divide by 8.
anonymous
  • anonymous
what does extraneous solution mean?
yamyam70
  • yamyam70
Correct! How would you tell if it is extraneous or not?
anonymous
  • anonymous
idk what that means.
yamyam70
  • yamyam70
We check the equation, by substituting the value of x. :)
anonymous
  • anonymous
i got 5=5
yamyam70
  • yamyam70
if you check it and the results of the left hand side is equal to the right hand side it is not extraneous :) if it does not equal , it is extraneous :)
anonymous
  • anonymous
oh ok thankyou!
yamyam70
  • yamyam70
Welcome to open study! please read the code of conduct if you have time :)
yamyam70
  • yamyam70
you're welcome :)
anonymous
  • anonymous
another question!
yamyam70
  • yamyam70
sure :)
anonymous
  • anonymous
Solve for x, given the equation \[\sqrt{x-5}+7=11\] x = 21, solution is extraneous x = 21, solution is not extraneous x = 81, solution is extraneous x = 81, solution is not extraneous
yamyam70
  • yamyam70
I see then same procedure, square both sides :)
anonymous
  • anonymous
x-5+49=121
yamyam70
  • yamyam70
oh wait, 7 isn't involved
yamyam70
  • yamyam70
one moment please
anonymous
  • anonymous
ok
yamyam70
  • yamyam70
are you sure about the given choices?
anonymous
  • anonymous
yes i got 77 but that answer was not there
yamyam70
  • yamyam70
I see, we got same, I'm trying a different approach, one moment
anonymous
  • anonymous
ok
yamyam70
  • yamyam70
okay here goes,
yamyam70
  • yamyam70
\[\sqrt{x-5} +7 =11\]
yamyam70
  • yamyam70
we tranfer 7 to the right hand side :)
yamyam70
  • yamyam70
what would we have?
anonymous
  • anonymous
\[\sqrt{x-5}=18\]
anonymous
  • anonymous
and then do we square both sides?
yamyam70
  • yamyam70
wrong :) , when we tranfer 7 , we change the signs right? :)
anonymous
  • anonymous
yes the right side is supposed to be 4
yamyam70
  • yamyam70
correct :) then we square both sides, the equation should look like \[\sqrt{x-5} = 4 \]
anonymous
  • anonymous
i got x= 17
yamyam70
  • yamyam70
wrong :) \[(\sqrt{x-5?})^2 = (4)\]
yamyam70
  • yamyam70
(x−5?−−−−−√)2=(4)^2
anonymous
  • anonymous
do i foil them?
yamyam70
  • yamyam70
wait nevermind that
yamyam70
  • yamyam70
\[(\sqrt{x-5})^2=(4)^2\]
yamyam70
  • yamyam70
^^^^^^ thats the correct one
anonymous
  • anonymous
so how to i solve for that?
yamyam70
  • yamyam70
remember when we square , \[\sqrt{x-5}\] it will give us x-5 :)
yamyam70
  • yamyam70
\[(\sqrt{x-5}) (\sqrt{x-5}) = x-5\]
anonymous
  • anonymous
x=21
yamyam70
  • yamyam70
correct :) , so check if it is extraneous or not :)
anonymous
  • anonymous
it is not
yamyam70
  • yamyam70
Correct :)
anonymous
  • anonymous
Given the equation \[\sqrt[-4]{x-3}=12\], solve for x and identify if it is an extraneous solution. x = 0, solution is not extraneous x = 0, solution is extraneous x = 12, solution is not extraneous x = 12, solution is extraneous
yamyam70
  • yamyam70
is that -4 ?
anonymous
  • anonymous
yes
anonymous
  • anonymous
would it be this \[x-3\frac{ 1 }{ -4}=12\]
yamyam70
  • yamyam70
hmm, I'm not quite sure about the rule here.
yamyam70
  • yamyam70
I would suggest too start another session. :)
yamyam70
  • yamyam70
I'm sorry , I can't help you with this one :)
anonymous
  • anonymous
ok thanks for the help
yamyam70
  • yamyam70
Bye :)
yamyam70
  • yamyam70
Don't forget to close the question :)
anonymous
  • anonymous
how do i do that?
yamyam70
  • yamyam70
On the left side, there is a timer, "bump in" beside it click close. :)

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