anonymous
  • anonymous
Find an equation of the circle that satisfies the given conditions. Endpoints of a diameter are P(−2, 1) and Q(8, 9).
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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zzr0ck3r
  • zzr0ck3r
equation of a circle\[(x-x_0)^2+(y-y_0)^2=r^2\]
zzr0ck3r
  • zzr0ck3r
now use the points given to find the radius
anonymous
  • anonymous
the circle has that point as center which is the midpoint of diameter and radius is distance between diameter ends/2

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anonymous
  • anonymous
what?
zzr0ck3r
  • zzr0ck3r
the equation of a circle is \[(x-x_0)^2+(y-y_0)^2=r^2\\where\space (x_0,y_0)\text{ is the center}\\\text{to find the radius we use the distance formula with the two points given}\] \[r=\sqrt{(8-(-2))^2+(9-1)^2}=\sqrt{164}\]so you have \[(x-8)^2+(y-9)^2=164\]
anonymous
  • anonymous
so that is the answer?

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