anonymous
  • anonymous
Prove the Converse of the Pythagorean Theorem using similar triangles. The Converse of the Pythagorean Theorem states that when the sum of the squares of the lengths of the legs of the triangle equals the squared length of the hypotenuse, the triangle is a right triangle. Be sure to create and name the appropriate geometric figures.
Mathematics
  • Stacey Warren - Expert brainly.com
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katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
@ash2326 @aaronq @andriod09 @BulletWithButterflyWings @BostonBlue @e.mccormick @Erin001001 @stabar @iiamentertainment @jhonyy9 @goformit100 @hba @Haunted9 @lncognlto @rizwan_uet can someone help
anonymous
  • anonymous
i am not good at math so idk
anonymous
  • anonymous
ok thx anyways :)

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More answers

zzr0ck3r
  • zzr0ck3r
http://www.qc.edu.hk/math/Junior%20Secondary/Converse%20of%20Py%20th.htm
zzr0ck3r
  • zzr0ck3r
I hate to just post that, but I cant draw on my tablet
zzr0ck3r
  • zzr0ck3r
tell me if you dont understand something
anonymous
  • anonymous
ok but thank you :)
anonymous
  • anonymous
EF = BC = a ÐF is a right angle. FD = CA = b triangle EF = BC = a angle F is a right angle. FD = CA = b In triangle DEF, By Pythagoras Theorem, a2 + b2 = c2 the given AB=c= a^2 + b^2 square root Theorefore AB = DE But by construction, BC = EF and CA = FD triangle ABC congruent to DEF (S.S.S.)
anonymous
  • anonymous
like this?
zzr0ck3r
  • zzr0ck3r
yep, as long as you understand it.
anonymous
  • anonymous
and i have this question
1 Attachment
anonymous
  • anonymous
i do and thanks to you :D the link explains everything :)
anonymous
  • anonymous
@skullpatrol @phi @Flisk
phi
  • phi
use asa
anonymous
  • anonymous
can you show and explain ? :)
phi
  • phi
you are given angle B= < F
anonymous
  • anonymous
prove two angles are the same and a side?
phi
  • phi
yes, but what angles and side are we going to use ?
phi
  • phi
anonymous
  • anonymous
so thats given to
anonymous
  • anonymous
ok :)
phi
  • phi
almost. DF = DB, but we need to show EF= CB
phi
  • phi
but notice EF= DF - DC and CB= DB-DE if you know DC= DE, and DF= DB then the difference will be the same
phi
  • phi
so you need to know why DC= DE I would use isosceles triangle idea... if base angles are equal, then the opposite sides are equal
anonymous
  • anonymous
now i have to put the proof in order
phi
  • phi
yes, lots of details but the big picture is angle - side -angle
anonymous
  • anonymous
given: angle B= < F
anonymous
  • anonymous
phi
  • phi
I hope you mean
phi
  • phi
we are doing the angles first. why is angle ACB = angle FEG ? you start by saying
phi
  • phi
if
anonymous
  • anonymous
angle sides angle?
phi
  • phi
I guess this does not make sense to you. notice that
anonymous
  • anonymous
well yah your rite it does not make sense but i get the first part up to vertical angles
anonymous
  • anonymous
really ok that looks simple !
phi
  • phi
you need the idea that if two different things equal the same thing then they equal each other. for example, if A = C and B=C then A=B this is common sense, so it should make a little sense. For this problem you say
phi
  • phi
that is the whole sequence to show
phi
  • phi
now tackle the side part. First step.
anonymous
  • anonymous
but isnt there at the end ASA?
anonymous
  • anonymous
vertical angles
phi
  • phi
the stuff to show
anonymous
  • anonymous
corresponding sides so..
phi
  • phi
First step.
anonymous
  • anonymous
If two angles of a triangle are congruent, the sides opposite them are congruent. this
phi
  • phi
yes. Do you follow what it says? we are given the base angles are =, so using this theorem (which has been proven by some smart person) we *know* the opposite sides (DC and DE) are equal
anonymous
  • anonymous
yahh i get it now :) thank you for that! ^_^
phi
  • phi
now we know DC +CB= DB
anonymous
  • anonymous
ok
phi
  • phi
now we know DC +CB= DB sum of parts equal the whole and DE+EF= DF sum of parts equal the whole DB= DF given so we can say DC +CB= DF (replace DB with DF) and DC+CB = DE+EF things equal to the same thing are equal to each other we just proved DC= DE so we can say DC+CB= DC+EF (replace DE with DC) CB= EF (subtracting equal amounts keeps the equality)
phi
  • phi
that proves the sides the last part, is
anonymous
  • anonymous
wow that was a long answer and im sure your tired of all this typing im sorry and thank you so so so much for all you help!!
phi
  • phi
yes, lots of details.
anonymous
  • anonymous
@bayan are u still in geometry can u help me

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