anonymous
  • anonymous
H= 3a + 5b -4c solve for a
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
a = (H-5b+4c)/3
anonymous
  • anonymous
Algebra
anonymous
  • anonymous
whats the steps in getting that answer? @stoopkid

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anonymous
  • anonymous
1) Subtract all the terms not containing a from both sides: so subtract 5b then subtract -4a (add 4a). 2) You are left with a single term containing a. Divide everything in this term that is not a from both sides, i.e. divide both sides by 3. Let me show you: H = 3a + 5b - 4c 1) The term 5b does not contain a, so subtract it. H - 5b = 3a - 4c 2) The term -4c does not contain a, so subtract it. H - 5b + 4c = 3a 3) Divide everything that is not a in the term 3a. (H - 5b + 4c)/3 = a

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