anonymous
  • anonymous
How many 5-digit numbers can be formed (using 0-9) without repetition?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
let's look at this with 4 numbers first if you can't repeat than you get 1234, 1243 1324 1342 1423 1432etc. basicly for each position you have 4 options on the first postion you can still pick each number so 4, on the second position you can only pick from 3 different numbers (since you can't repeat.) so eventually your amount of options is multiplied to: 4*3*2*1 = 24 options. (you can check this by writing it out.) in the same way solve for 9numbers

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