anonymous
  • anonymous
Help pleaseeeee!(: The position of an object as a function of time is given by x = At2 – Bt + C, where A = 8.7 m/s2, B = 5.5 m/s, and C = 4.3 m. Find the instantaneous velocity and acceleration as functions of time. (Use the following as necessary: t.) V=_______ a=_______
Physics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
V=dx/dt V=2At-B a=dv/dt you can find a.
anonymous
  • anonymous
how do i find dv and dt?
anonymous
  • anonymous
dv/dt refers to derivative of v to t. So a=2A

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
so a would be a=2(8.7)m/s^2 ? a=17.4 m/s^2?
anonymous
  • anonymous
@Loser66
Loser66
  • Loser66
\[v = \frac{dx}{dt}\] and \[a = \frac{d^2x}{dt^2}\] that's it.
Loser66
  • Loser66
for v, take the first derivative of x , then, plug the value of letter in. for a, take second derivative of x, then ,plug the value of letter in. Done.
Loser66
  • Loser66
got me?
anonymous
  • anonymous
so far yes. but how do i obtain the values of dx,dt, d^2x and dt^2? @Loser66
Loser66
  • Loser66
don't you know how to take derivative?
anonymous
  • anonymous
what am i taking the derivative of? x=At^2-Bt+C?
Loser66
  • Loser66
yes, it is.
Loser66
  • Loser66
you see, x =.... is a function of t or you can write it as x(t)
anonymous
  • anonymous
x(t)=At^2-Bt+C ? Sorry I'm a bit confused
Loser66
  • Loser66
which grade are you? college? highschool?
anonymous
  • anonymous
college, and I'm struggling badly /; with this and another problem
Loser66
  • Loser66
how about calculus?
Loser66
  • Loser66
I have to know where are you to give out the appropriate instruction.
anonymous
  • anonymous
I took calculus, just trying to recall thing from it..
Loser66
  • Loser66
ok, (t^3)' =?
anonymous
  • anonymous
3t^2?
Loser66
  • Loser66
yes, so, (At^2)' =?
anonymous
  • anonymous
2At?
Loser66
  • Loser66
hahaha.. dan, guide him, please, don't just give out the answer
dan815
  • dan815
v=d/dt(f(t))
anonymous
  • anonymous
i'm a her.
dan815
  • dan815
do you know v=d/t formula
dan815
  • dan815
speed my definition is distance travelled per unit time
anonymous
  • anonymous
velocity= distance/time
dan815
  • dan815
velocity=displacement/time but okay
dan815
  • dan815
lets move on!
dan815
  • dan815
now you have a function here f(t)=x
dan815
  • dan815
|dw:1378843024659:dw|
anonymous
  • anonymous
okay. understanding so far..
dan815
  • dan815
this graph the position is changing non linearly
dan815
  • dan815
for example, can you see that if the graph was like this |dw:1378843104053:dw|
dan815
  • dan815
|dw:1378843156111:dw|
dan815
  • dan815
the idea of instaneous velocity is to measure the change in x for very small changed in t because
dan815
  • dan815
the smalled the t is the shape is more like a line
dan815
  • dan815
|dw:1378843265278:dw|
dan815
  • dan815
now i dont wanna go back into first principles definition of derivative but you should know that stuff
dan815
  • dan815
basically this is why we can take the derivative of this function to calculate the instaneous velocity for any function linear or non linear, as long as its continous and a valid function
dan815
  • dan815
|dw:1378843369865:dw|
dan815
  • dan815
|dw:1378843438614:dw|
dan815
  • dan815
instaneous velocity is the velocity at just the point in other words we decrease the length of the line to be 0, which happens as change in time approaches 0
anonymous
  • anonymous
okay... i kinda got lost, so m= change of y/ change of t which =dx/dt?
dan815
  • dan815
there is no y here its x but yes
dan815
  • dan815
m=slope
dan815
  • dan815
instanous velocity at a point = the slope of the tangent line at a point
dan815
  • dan815
in other words the derivative of x evaluated at a point
anonymous
  • anonymous
okay so having that v=d/dt(f(t))?
dan815
  • dan815
|dw:1378843613053:dw|
dan815
  • dan815
|dw:1378843689508:dw|
anonymous
  • anonymous
wait so the velocity would be 17.4 m/s/s and that was just taking the derivative of dx/dt?
dan815
  • dan815
the first derivative = velocity the 2nd derivative = acceleration

Looking for something else?

Not the answer you are looking for? Search for more explanations.