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the 1 does not apply and that s not even an option
this is not a trick question one of the answers is correct and it is not 6
and even if it was 25 you would divide it by 5 to get 5 and that isn't a option
keep in mind that the first amount of tv's is 0 but you do have to add it when you devide by the number of households
the mean is the most often used number, so you can find the answer by taking every tally and multiplying it by the number of sets, then divide it by the number of students. (0*1) + (1*8) + (2*9) + (3*4) + (4*3) = 50 50 / ( 1 + 8 + 9 + 4 + 3 ) = 2
it says WORKING° TV's also
no that is mode
assume all listed tv's are working
mode is most often used, sorry, mean is the average.
the mode would be 2 as well though.
but one kid deasnt have a tv so that doesn't count
he does count, he has 0 working T.V.'s in his house, so his data still matters.
it does count towards the number of households, not towards the tvs
hold on a minute
so then that is 24 / 5
why would it be 24/5? xD
24 ÷ 5
I explained how the mean works and how you can find it with data sets, look at my first responce.
/ = ÷
but, it still would be 2 wouldn't it?
I don't get it thou
I shouldn't have to go through that proccess
it should be 1 + 8 + 9 + 4 + 3 ÷ 5
but, that doesnt work
but you're finding the average number o T.V. sets, not the average number of people with a non-zero amount of T.V. sets in a given classroom.
OHHHHHHHH, I GET IT NOW
that, I feel like an idiot, maybe I am D:
you're actually counting each T.V. set, so the long math would look like 0+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+3+3+3+3+4+4+4 / however many students there are
needs more 2s n' stuff, but you get the point, rather than typing two nine times, you can just type (2*9)