Trick question?

- anonymous

Trick question?

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- anonymous

##### 1 Attachment

- anonymous

6.25

- anonymous

the 1 does not apply and that s not even an option

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- anonymous

THAN 6

- anonymous

this is not a trick question one of the answers is correct and it is not 6

- anonymous

and even if it was 25 you would divide it by 5 to get 5 and that isn't a option

- anonymous

@Preetha

- anonymous

keep in mind that the first amount of tv's is 0 but you do have to add it when you devide by the number of households

- anonymous

the mean is the most often used number, so you can find the answer by taking every tally and multiplying it by the number of sets, then divide it by the number of students.
(0*1) + (1*8) + (2*9) + (3*4) + (4*3) = 50
50 / ( 1 + 8 + 9 + 4 + 3 ) = 2

- anonymous

it says WORKING° TV's also

- anonymous

no that is mode

- anonymous

assume all listed tv's are working

- anonymous

mode is most often used, sorry, mean is the average.

- anonymous

the mode would be 2 as well though.

- anonymous

but one kid deasnt have a tv so that doesn't count

- anonymous

doesnt*

- anonymous

he does count, he has 0 working T.V.'s in his house, so his data still matters.

- anonymous

it does count towards the number of households, not towards the tvs

- anonymous

hold on a minute

- anonymous

so then that is 24 / 5

- anonymous

24/5?

- anonymous

divided

- anonymous

why would it be 24/5? xD

- anonymous

24 ÷ 5

- anonymous

I explained how the mean works and how you can find it with data sets, look at my first responce.

- anonymous

/ = ÷

- anonymous

@amistre64

- anonymous

but, it still would be 2 wouldn't it?

- anonymous

yes

- anonymous

I don't get it thou

- anonymous

I shouldn't have to go through that proccess

- anonymous

why not?

- anonymous

it should be 1 + 8 + 9 + 4 + 3 ÷ 5

- anonymous

simple

- anonymous

but, that doesnt work

- anonymous

but you're finding the average number o T.V. sets, not the average number of people with a non-zero amount of T.V. sets in a given classroom.

- anonymous

OHHHHHHHH, I GET IT NOW

- anonymous

that, I feel like an idiot, maybe I am D:

- anonymous

you're actually counting each T.V. set, so the long math would look like
0+1+1+1+1+1+1+1+1+2+2+2+2+2+2+2+2+2+3+3+3+3+4+4+4 / however many students there are

- anonymous

needs more 2s n' stuff, but you get the point, rather than typing two nine times, you can just type (2*9)

- anonymous

Thanks ☺

- anonymous

np

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