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galacticwavesXX Group Title

Can someone help me with my java code? i am stuck on how to come up with an mathematical equation that can take any amount between 0 - 999.99 and break it into smaller monetary amounts

  • one year ago
  • one year ago

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  1. galacticwavesXX Group Title
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    my code so far is import java.util.Scanner; //Need Scanner class public class Money { public static void main(String[] args) { double amount; //To hold the monetary amount int newAmount; //To hold the total amount of Dollars double amount_Of_Coins; //To hold the total amount of coins int bill20, bill10, bill5, bill1; //To hold the units of bills of the monetary amount int coin25, coin10, coin5,coin1; //To hold the units of coins of the monetary amount Scanner keyboard = new Scanner(System.in); //Ask the user for the monetary amount System.out.println("Enter a monetary amount between 0 - 999.99: "); amount = keyboard.nextDouble(); newAmount = (int)amount;

    • one year ago
  2. e.mccormick Group Title
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    You can use division and subtraction to split off parts.

    • one year ago
  3. galacticwavesXX Group Title
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    So for the division i can use to split the left side and right side of a value....supposing the value was 36.41. Subtraction could be used to calculate the amount of coins there are for quarters, dimes, nickels and pennies, right?

    • one year ago
  4. e.mccormick Group Title
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    $432.11 First, *100 to get it into integer math. 43211 Divide by 10000 to find the number of 100 bills. b100 = 4 Subtract 4*b100 to get 3211. Divide by 2000 to get the number of $20 bills. b20=1 and so on...

    • one year ago
  5. galacticwavesXX Group Title
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    im sorry openstudy just stopped working for the longest so i couldn't do anything but try to get the code working a little. I got the dollar bills to work fine...now im stuck on the coins.

    • one year ago
  6. galacticwavesXX Group Title
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    the code i have so far is: import java.util.Scanner; //Need Scanner class public class Money { public static void main(String[] args) { double amount; //To hold the monetary amount Scanner keyboard = new Scanner(System.in); //Ask the user for the monetary amount System.out.println("Enter a monetary amount between 0 - 999.99: "); amount = keyboard.nextDouble(); int newAmount; //To hold new amount newAmount = (int)amount; int bill20 = newAmount/20; newAmount %= 20; int bill10 = newAmount/10; newAmount %= 10; int bill5 = newAmount/5; newAmount %= 5; int bill1 = newAmount/1; newAmount %= 1; System.out.println(bill20 + " amount of 20 dollar bills"); System.out.println(bill10 + " amount of 10 dollar bills"); System.out.println(bill5 + " amount of 5 dollar bills"); System.out.println(bill1 + " amount of 1 dollar bills");

    • one year ago
  7. galacticwavesXX Group Title
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    @thomaster can you help me on how to solve for coins in my java program?

    • one year ago
  8. e.mccormick Group Title
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    That is why I said start with multiplying by 100. But if you get it don to just the coins, you could multiply by 100 there and then it is the same basic thing.

    • one year ago
  9. galacticwavesXX Group Title
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    So using your example of $432.11, for doing it with the dollar bills i'm multiplying 432.11 * 100. or just in the form .11 * 100 part?

    • one year ago
  10. e.mccormick Group Title
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    Either way works, but you have the dollars work out. So you take the remainder, .11, and go from there. *100 and it will be cents as in per 100. /25 for quarters, mode 25 to get what is left to get the dimes, etc.

    • one year ago
  11. galacticwavesXX Group Title
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    ok so i can put in a mathematical operation such as dollar coin = newAmount - amount; since the user has to put an amount and see if the monetary system runs then get quarter = (coin * 100)/25; quarter %= 25;

    • one year ago
  12. galacticwavesXX Group Title
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    since it all has to be keyboard input

    • one year ago
  13. e.mccormick Group Title
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    To coninue the way you had it.... int bill1 = newAmount/1; newAmount %= 1; newAmount *= 100; int coin25 = newAmount/25; newAmount %= 25; int coin10 = newAmount/10; newAmount %= 10; int coin5 = newAmount/5; int coin1 = newAmount % 5;

    • one year ago
  14. e.mccormick Group Title
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    Hmmm.... looks like you already stripped the ints... so... more like: int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100)

    • one year ago
  15. e.mccormick Group Title
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    Then use that to find the cents...

    • one year ago
  16. e.mccormick Group Title
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    or to find the coins...

    • one year ago
  17. galacticwavesXX Group Title
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    ohh okay that makes more sense.... trying to calculate for the coins was tricky...i didnt know you had to multiply it by 100. but thanks man, you help me out a LOT!!

    • one year ago
  18. e.mccormick Group Title
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    Yah, the 100 is to change from a decimal to an int. Then everything else you did works.

    • one year ago
  19. galacticwavesXX Group Title
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    so i input int coin25 = newCents/25; newCents %= 25;

    • one year ago
  20. e.mccormick Group Title
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    Cent and percent have the same base. Per Centum, or Per 100. Well, per 100 has another representation: \(\dfrac{x}{100}\) It is the same thing about converting percentage.

    • one year ago
  21. galacticwavesXX Group Title
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    ohh so divide everything by 100 then

    • one year ago
  22. e.mccormick Group Title
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    Well, you want to go from a decimal to a whole number, so multiply by 100.

    • one year ago
  23. e.mccormick Group Title
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    \(\dfrac{x}{100}\cdot 100 = x\) And you want x cents. \(.11 \implies \dfrac{11}{100}\) and you want 11.

    • one year ago
  24. e.mccormick Group Title
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    Because you are going from .11 dollars to 11 cents. So really, unit conversion.

    • one year ago
  25. galacticwavesXX Group Title
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    ok so i should input int quarter = newCents * 100; that is what your saying

    • one year ago
  26. galacticwavesXX Group Title
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    i meant int coin25

    • one year ago
  27. e.mccormick Group Title
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    No, because newCents is the entire cents. Then you use the same thing you did before: int coin25 = newCents/25; newCents %= 25;

    • one year ago
  28. e.mccormick Group Title
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    Repeat for 10 and 5, no need to repeat for 1. Just use the %5 to get pennies.

    • one year ago
  29. e.mccormick Group Title
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    Oh, and you may notice that what you type here collapses when people paste it. If you put ``` above and below on a seperate line it will do proper coding. ``` int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100) ``` int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100) Try to copy and paste both of those.

    • one year ago
  30. galacticwavesXX Group Title
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    Ohh okay i get it now, so many little things to look into and know....i need to practice more on these kinds of programs you want me to copy and paste it here or on my program?

    • one year ago
  31. e.mccormick Group Title
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    I just meant for you to try it so you would know what I am talking about.

    • one year ago
  32. galacticwavesXX Group Title
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    int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100) int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100)

    • one year ago
  33. e.mccormick Group Title
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    For me it does this: int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100) int newAmount; //To hold new amount newAmount = (int)amount; int newCents; // To hold the cents newCents = (int)((amount-newAmount)*100)

    • one year ago
  34. e.mccormick Group Title
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    Note how it messes up the bottom? Whee.

    • one year ago
  35. e.mccormick Group Title
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    I wanted to do one detailed example because this actually applies to anything. Physics, geology, etc. you can use this. If you think of it in unit conversion terms it is a ratio: 1$:100¢ Therefore to find x$ in ¢, you set thing up as fractions. Now, to convert, the units you convert from must cancel. \(.11$ \implies \dfrac{11$}{100}\) Because $ is on the top, I need to set up my cancel ratio with it on the bottom: \(\dfrac{11$}{100}\cdot \dfrac{100¢}{1$}\implies \) \( \dfrac{11\bcancel{$}}{\cancel{100}} \cdot \dfrac{\cancel{100}¢}{1\bcancel{$}} \implies\) \( \dfrac{11}{1}\cdot \dfrac{¢}{1}=11¢\)

    • one year ago
  36. e.mccormick Group Title
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    If you have feet to inches or weight chanegs or anything with a unit change, that principal works.

    • one year ago
  37. galacticwavesXX Group Title
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    Yup i see it, i didnt know it made that much of a difference. so many things to know

    • one year ago
  38. e.mccormick Group Title
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    Well, it is just a general principal. In this case you are using it to get integer math for cents. Cause it makes sense... hehe.

    • one year ago
  39. galacticwavesXX Group Title
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    lol yeah its just when you program sometimes those general concepts slip out because of all the new language you need to remember or are trying to use properly

    • one year ago
  40. e.mccormick Group Title
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    Hehe. And it is a general concept in math and perhaps any other science you learned. That is why they teach all that math. It lets you use the general concepts in other things.

    • one year ago
  41. galacticwavesXX Group Title
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    Yeah with all the math classes i've taken they brought back geometry and algebra concepts but they weren't hard.....it's only the trig applied in calculus that kills integrity

    • one year ago
  42. e.mccormick Group Title
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    Well, calc uses evberything down to 1+1=2!

    • one year ago
  43. e.mccormick Group Title
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    \(\int x\rm dx\) when you do that, you add one to the power, right? \(\int x\rm dx\implies \int x^1\rm dx\implies \dfrac{x^{1+1}}{1+1}+c\) So in calculus you use 1+1=2. =)

    • one year ago
  44. galacticwavesXX Group Title
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    hahaha of course integration was fun even though there were so many kind of ways to do it, depending on the question given

    • one year ago
  45. e.mccormick Group Title
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    Yah. I just enjoy pointing out that everything finally comes together in math at about trig. From then on, it is "And you get to use everything you learned from preeschool on at this point." Parts of math before that seem unrelated or distant cousins at times. Once you hit trig, you use everything all at once. And calculus is the same, and inclused the trig. Linear Algebra can be used with calculus in it.... so really nasty at times. And so on.

    • one year ago
  46. galacticwavesXX Group Title
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    I'm in linear algebra right now.....Matrices seems too run the world and i just found out that Google is composed of matrices itself we are doing application problems to figure out if it has solutions or not, depending if the system is consistent or not working with matrices is a lot faster i might say

    • one year ago
  47. e.mccormick Group Title
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    Yah, it it invertable... does it have a determinant. Presto. Many qustions answered right there. Google uses a hash map. Hash maps can be represnted in matrices.

    • one year ago
  48. e.mccormick Group Title
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    This is one representation of the concept: http://www.alglib.net/matrixops/sparse.php

    • one year ago
  49. galacticwavesXX Group Title
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    Exactly makes solving problems less strenuous

    • one year ago
  50. e.mccormick Group Title
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    Another thing is you have rules about what is done. So you can apply the rules to the equation and get the result... let me see if I can find this thing. It was like an early question ansewered. Was not thinking when I did it the first time and redid it for the guy properly.

    • one year ago
  51. e.mccormick Group Title
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    http://openstudy.com/study#/updates/51677e75e4b050ab14bf429e

    • one year ago
  52. galacticwavesXX Group Title
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    Ok, i'm still trying to understand this sparse matrices concept but i'm looking at it and i'm like i haven't learned some these things yet

    • one year ago
  53. e.mccormick Group Title
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    I only went to intro linear myself, so there are tons I don't get. Hehe.

    • one year ago
  54. e.mccormick Group Title
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    Well, I am going to sneak off. Have fun!

    • one year ago
  55. galacticwavesXX Group Title
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    you too thanks for the help!

    • one year ago
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