anonymous
  • anonymous
What is the domain of this. I got x cant equal 3 and -3.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
umm i cant do the equation, but here it is. I'm trying my best. y=x+3/4-sqr (x^2-9)
jim_thompson5910
  • jim_thompson5910
The equation is \[\large y = \frac{x+3}{4-\sqrt{x^2-9}}\] right?
anonymous
  • anonymous
yea, it doesnt show as an equation when i write it on here tho. but i think u got it right

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jim_thompson5910
  • jim_thompson5910
so the equation given to you is in text form like that?
anonymous
  • anonymous
no no. the system on here is showing it in text
jim_thompson5910
  • jim_thompson5910
but what I wrote is what they gave you?
anonymous
  • anonymous
yes
jim_thompson5910
  • jim_thompson5910
ok you first need to solve x^2 - 9 >= 0 for x
anonymous
  • anonymous
i did i got -3 and 3
jim_thompson5910
  • jim_thompson5910
that's if you solve x^2 - 9 = 0
jim_thompson5910
  • jim_thompson5910
it's slightly different solving x^2 - 9 >= 0 , but -3 and 3 are involved
jim_thompson5910
  • jim_thompson5910
a visual way to solve x^2 - 9 >= 0 is to look at the graph of x^2 - 9 and note where it is above the x axis well this is for the intervals (-infinity, -3) and (3, infinity) and you use a graph to see this therefore, the solution for x^2 - 9 >= 0 in interval notation is (-infinity, -3) U (3, infinity)
jim_thompson5910
  • jim_thompson5910
the last thing you need to do is make sure the denominator is not zero (since you cannot divide by zero)
anonymous
  • anonymous
the answer also gives me 5 and -5
jim_thompson5910
  • jim_thompson5910
you need to solve \[\large 4-\sqrt{x^2-9}=0\] for x
jim_thompson5910
  • jim_thompson5910
hopefully you can see how solving that leads you to x = 5 or x = -5 these two values must be excluded from the domain (to avoid division by zero)
anonymous
  • anonymous
ok thank you
jim_thompson5910
  • jim_thompson5910
yw

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