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First let's isolate x
-4x - 5 > -9 -4x - 5+5 > -9+5 ... Add 5 to both sides. -4x > -4 -4x/(-4) < -4/(-4) .. Divide both sides by -4 (notice the sign flips). x < 1
let me know if that makes sense, if so, then we'll move onto the graph
ok so will that be an open or closed graph
there is no line under the inequality sign, so you exclude the endpoint
you show this with an open circle
so you'll do this step 1) draw a number line step 2) plot an open circle at 1 step 3) shade to the left of the open circle
ok thank u so much i have another question if you can help\
ok -2y - 7 > 11 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution.
show me what you got so far
ok -2x -7+7 > -11+7; simplify i think
so far so good
btw you have x instead of y, but it's no big deal really (silly typo)
-2x > -2 ; divide by -2 and switch the sign
-2x -7+7 > -11+7; simplify
and then -2x-7+7>-11+7
switch the sign then -4x/-2 < -2/-2
hmm that's a bit off
here's what you should get
-2y - 7 > 11 -2y - 7+7 > 11+7 -2y > 18 -2y/(-2) < 18/(-2) y < -9
I'll let you handle the graph portion
ok i get where i messed up thank you but i have another ???
ok last one
ok 16 < 3x + 1 < 4 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution.
are you sure that's 16? or is it -16?
isolate x to get 16 < 3x + 1 < 4 16-1 < 3x + 1-1 < 4-1 ... Subtract 1 from all sides. 15 < 3x < 3 15/3 < 3x/3 < 3/3 ... Divide all sides by 3. 5 < x < 1 since it's impossible for a number to be both larger than 5 AND smaller than 1 at the same time, the statement 5 < x < 1 is always false so 16 < 3x + 1 < 4 is always false
ok so thats it
yes, there are no solutions
because 16 < 3x + 1 < 4 is false
oh ok i get it now thank you so much jim you really helped alot ;)
you're welcome, I'm glad to be of help
:) YOUR THE BEST
thanks, hopefully you'll be able to do the rest with what you learned here
YES I WILL THANKKKKK UUUUUU