anonymous
  • anonymous
Solve -4x - 5 > -9 and describe the graph of the solution help please!!!!!
Algebra
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
First let's isolate x
jim_thompson5910
  • jim_thompson5910
-4x - 5 > -9 -4x - 5+5 > -9+5 ... Add 5 to both sides. -4x > -4 -4x/(-4) < -4/(-4) .. Divide both sides by -4 (notice the sign flips). x < 1
jim_thompson5910
  • jim_thompson5910
let me know if that makes sense, if so, then we'll move onto the graph

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More answers

anonymous
  • anonymous
ok so will that be an open or closed graph
jim_thompson5910
  • jim_thompson5910
there is no line under the inequality sign, so you exclude the endpoint
jim_thompson5910
  • jim_thompson5910
you show this with an open circle
jim_thompson5910
  • jim_thompson5910
so you'll do this step 1) draw a number line step 2) plot an open circle at 1 step 3) shade to the left of the open circle
anonymous
  • anonymous
ok thank u so much i have another question if you can help\
jim_thompson5910
  • jim_thompson5910
sure
anonymous
  • anonymous
ok -2y - 7 > 11 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution.
jim_thompson5910
  • jim_thompson5910
show me what you got so far
anonymous
  • anonymous
ok -2x -7+7 > -11+7; simplify i think
jim_thompson5910
  • jim_thompson5910
so far so good
jim_thompson5910
  • jim_thompson5910
btw you have x instead of y, but it's no big deal really (silly typo)
anonymous
  • anonymous
-2x > -2 ; divide by -2 and switch the sign
anonymous
  • anonymous
wrong one
anonymous
  • anonymous
-2x -7+7 > -11+7; simplify
anonymous
  • anonymous
and then -2x-7+7>-11+7
anonymous
  • anonymous
switch the sign then -4x/-2 < -2/-2
jim_thompson5910
  • jim_thompson5910
hmm that's a bit off
anonymous
  • anonymous
oh
jim_thompson5910
  • jim_thompson5910
here's what you should get
jim_thompson5910
  • jim_thompson5910
-2y - 7 > 11 -2y - 7+7 > 11+7 -2y > 18 -2y/(-2) < 18/(-2) y < -9
jim_thompson5910
  • jim_thompson5910
I'll let you handle the graph portion
anonymous
  • anonymous
ok i get where i messed up thank you but i have another ???
jim_thompson5910
  • jim_thompson5910
ok last one
anonymous
  • anonymous
ok 16 < 3x + 1 < 4 Part 1: Solve the inequality above. Part 2: Describe the graph of the solution.
anonymous
  • anonymous
thank u
jim_thompson5910
  • jim_thompson5910
are you sure that's 16? or is it -16?
anonymous
  • anonymous
its 16
jim_thompson5910
  • jim_thompson5910
ok
jim_thompson5910
  • jim_thompson5910
isolate x to get 16 < 3x + 1 < 4 16-1 < 3x + 1-1 < 4-1 ... Subtract 1 from all sides. 15 < 3x < 3 15/3 < 3x/3 < 3/3 ... Divide all sides by 3. 5 < x < 1 since it's impossible for a number to be both larger than 5 AND smaller than 1 at the same time, the statement 5 < x < 1 is always false so 16 < 3x + 1 < 4 is always false
anonymous
  • anonymous
ok so thats it
jim_thompson5910
  • jim_thompson5910
yes, there are no solutions
jim_thompson5910
  • jim_thompson5910
because 16 < 3x + 1 < 4 is false
anonymous
  • anonymous
oh ok i get it now thank you so much jim you really helped alot ;)
jim_thompson5910
  • jim_thompson5910
you're welcome, I'm glad to be of help
anonymous
  • anonymous
:) YOUR THE BEST
jim_thompson5910
  • jim_thompson5910
thanks, hopefully you'll be able to do the rest with what you learned here
anonymous
  • anonymous
YES I WILL THANKKKKK UUUUUU

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