hkmiu
  • hkmiu
x(x+2) / x(x-3) would the holes be x=-2 & x=3 or just x=3?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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jim_thompson5910
  • jim_thompson5910
hint: solve x(x-3) = 0
hkmiu
  • hkmiu
well both -2 and 3 are equals to 0
jim_thompson5910
  • jim_thompson5910
oh wait, the 'x' terms will cancel

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jim_thompson5910
  • jim_thompson5910
x(x+2) / x(x-3) would turn into (x+2)/(x-3)
jim_thompson5910
  • jim_thompson5910
So this means that there is a vertical asymptote at x = 3 and there's a hole at x = 0 because this value must be excluded as well
hkmiu
  • hkmiu
Waittt, but the (x+2) won't have anything to do with it because that's used for determining the horizontal only right?
jim_thompson5910
  • jim_thompson5910
the x+2 in the numerator plays no role in figuring out vertical asymptotes or holes (unless it canceled with a x+2 in the denominator)
jim_thompson5910
  • jim_thompson5910
the leading coefficients determine the horizontal asymptote
hkmiu
  • hkmiu
thanks!
jim_thompson5910
  • jim_thompson5910
you're welcome

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