anonymous
  • anonymous
Find the domain of the expression: 1. 6x^2-9, x>0 2. (x^2-x-12)/(x^2-8+16) Please show steps or explain them to me! Thank you!
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
-9
anonymous
  • anonymous
is it like all real numbers, or can you please explain?
anonymous
  • anonymous
yes

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
it still does not make sense, x has to be > 0
anonymous
  • anonymous
the real numer has negive
anonymous
  • anonymous
@jim_thompson5910 can you help me with these two problems?
jim_thompson5910
  • jim_thompson5910
by default, all polynomials have a domain of the set of all real numbers
jim_thompson5910
  • jim_thompson5910
but because it clearly states that x > 0, that means the domain is x > 0, so the domain is the set of positive real numbers
jim_thompson5910
  • jim_thompson5910
to find the domain of (x^2-x-12)/(x^2-8x+16), set the denominator equal to zero and solve for x those two solutions will be values you exclude from the domain
anonymous
  • anonymous
Thank you! Now my answers are: 1. x=all + real numbers 2. x cannot=+ or - 4, and -2 is that right?
jim_thompson5910
  • jim_thompson5910
the first one is correct, but the second is not
jim_thompson5910
  • jim_thompson5910
hint: x^2 - 8x + 16 factors to (x-4)(x-4)
anonymous
  • anonymous
so x cannot equal 4, or -2 ?
jim_thompson5910
  • jim_thompson5910
how are you getting -2?
anonymous
  • anonymous
oh nevermind I see what I was doing wrong, was separating x^2 and -8x and solving them each for -16 separately. So the answer is just x cannot = 4 ?
jim_thompson5910
  • jim_thompson5910
bingo, the domain is the set of all real numbers but x cannot equal 4
anonymous
  • anonymous
Okay thank you! :)
jim_thompson5910
  • jim_thompson5910
you're welcome

Looking for something else?

Not the answer you are looking for? Search for more explanations.