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Find the domain of the expression:
1. 6x^29, x>0
2. (x^2x12)/(x^28+16)
Please show steps or explain them to me! Thank you!
 7 months ago
 7 months ago
Find the domain of the expression: 1. 6x^29, x>0 2. (x^2x12)/(x^28+16) Please show steps or explain them to me! Thank you!
 7 months ago
 7 months ago

This Question is Closed

greeneyes<3Best ResponseYou've already chosen the best response.1
is it like all real numbers, or can you please explain?
 7 months ago

greeneyes<3Best ResponseYou've already chosen the best response.1
it still does not make sense, x has to be > 0
 7 months ago

munaaliBest ResponseYou've already chosen the best response.0
the real numer has negive
 7 months ago

greeneyes<3Best ResponseYou've already chosen the best response.1
@jim_thompson5910 can you help me with these two problems?
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
by default, all polynomials have a domain of the set of all real numbers
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
but because it clearly states that x > 0, that means the domain is x > 0, so the domain is the set of positive real numbers
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
to find the domain of (x^2x12)/(x^28x+16), set the denominator equal to zero and solve for x those two solutions will be values you exclude from the domain
 7 months ago

greeneyes<3Best ResponseYou've already chosen the best response.1
Thank you! Now my answers are: 1. x=all + real numbers 2. x cannot=+ or  4, and 2 is that right?
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
the first one is correct, but the second is not
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
hint: x^2  8x + 16 factors to (x4)(x4)
 7 months ago

greeneyes<3Best ResponseYou've already chosen the best response.1
so x cannot equal 4, or 2 ?
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
how are you getting 2?
 7 months ago

greeneyes<3Best ResponseYou've already chosen the best response.1
oh nevermind I see what I was doing wrong, was separating x^2 and 8x and solving them each for 16 separately. So the answer is just x cannot = 4 ?
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
bingo, the domain is the set of all real numbers but x cannot equal 4
 7 months ago

greeneyes<3Best ResponseYou've already chosen the best response.1
Okay thank you! :)
 7 months ago

jim_thompson5910Best ResponseYou've already chosen the best response.1
you're welcome
 7 months ago
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