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is it like all real numbers, or can you please explain?
it still does not make sense, x has to be > 0
the real numer has negive
@jim_thompson5910 can you help me with these two problems?
by default, all polynomials have a domain of the set of all real numbers
but because it clearly states that x > 0, that means the domain is x > 0, so the domain is the set of positive real numbers
to find the domain of (x^2-x-12)/(x^2-8x+16), set the denominator equal to zero and solve for x those two solutions will be values you exclude from the domain
Thank you! Now my answers are: 1. x=all + real numbers 2. x cannot=+ or - 4, and -2 is that right?
the first one is correct, but the second is not
hint: x^2 - 8x + 16 factors to (x-4)(x-4)
so x cannot equal 4, or -2 ?
how are you getting -2?
oh nevermind I see what I was doing wrong, was separating x^2 and -8x and solving them each for -16 separately. So the answer is just x cannot = 4 ?
bingo, the domain is the set of all real numbers but x cannot equal 4
Okay thank you! :)