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anonymous
 3 years ago
Find the domain of the expression:
1. 6x^29, x>0
2. (x^2x12)/(x^28+16)
Please show steps or explain them to me! Thank you!
anonymous
 3 years ago
Find the domain of the expression: 1. 6x^29, x>0 2. (x^2x12)/(x^28+16) Please show steps or explain them to me! Thank you!

This Question is Closed

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0is it like all real numbers, or can you please explain?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it still does not make sense, x has to be > 0

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the real numer has negive

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@jim_thompson5910 can you help me with these two problems?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1by default, all polynomials have a domain of the set of all real numbers

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1but because it clearly states that x > 0, that means the domain is x > 0, so the domain is the set of positive real numbers

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1to find the domain of (x^2x12)/(x^28x+16), set the denominator equal to zero and solve for x those two solutions will be values you exclude from the domain

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Thank you! Now my answers are: 1. x=all + real numbers 2. x cannot=+ or  4, and 2 is that right?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1the first one is correct, but the second is not

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1hint: x^2  8x + 16 factors to (x4)(x4)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0so x cannot equal 4, or 2 ?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1how are you getting 2?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0oh nevermind I see what I was doing wrong, was separating x^2 and 8x and solving them each for 16 separately. So the answer is just x cannot = 4 ?

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1bingo, the domain is the set of all real numbers but x cannot equal 4

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.1you're welcome
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