anonymous
  • anonymous
Sketch the graph of a single function f that has the following properties. NOTE: There are many correct answers. •f(-2)=3 •lim f(x) does not exist x--> -2 •lim f(x)=-2 x--> 2+ •f(4)=5 •f(x)=2 x-->4 How would I do this? Is there a way anyone can show me? o.O We never did graphs in class yet. Is there a link or a process of how to do this that anyone can show me?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
make a function that jumps at \((-2,3)\)
anonymous
  • anonymous
ok i screwed that all up, i should learn to read
anonymous
  • anonymous
\(f(-2)=3\) means the point \((-2,3)\) is on the graph \[\lim_{x\to -2}f(x)\] does not exist means there is some sort of discontinuity there, a jump will work nicely

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anonymous
  • anonymous
is number 3 this \[\lim_{x\to 2^+}f(x)=-2\] or this \[\lim_{x\to -2^+}f(x)=-2\]
anonymous
  • anonymous
it will make a difference, and i am thinking it might be the second, even though you wrote the first
anonymous
  • anonymous
It was supposed to be the first one. Not the second one
anonymous
  • anonymous
ok
anonymous
  • anonymous
lets take care of the first two first
anonymous
  • anonymous
|dw:1378869888841:dw|
anonymous
  • anonymous
circle closed at \((-2,3)\) means \(f(-2)=3\) and the jump means the limit at \(-2\) does not exist
anonymous
  • anonymous
more or less clear?
anonymous
  • anonymous
What do you mean by "the limit at −2 does not exist" :O

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