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Tangent line or something else?
find the slope with given point, f(theta)= 4sin(theta)-theta i know the derivative would be -4cos(theta)- something, so is that something one or zero, basically the derivative of theta?
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Derivative would be -4sin(theta) and yes, derivative of theta is just 0. Its just as if it were an x.
Oh, sorry, 1 then x_x
Brain being dumb.
why 1 and not zero that is where im somewhat confused
Well, theta is just a variable. if it weren't a variable, we'd have nothing to plug 0 into when we try to find the slope. So we have to act like this is actually
4cos(x) - x
Inw hich case the derivative of x is just 1 and 4cosx becomes -4sinx
oh okay thanks because i knew it wasnt a constant
yeah, my brain wentdumb on me. SO yeah, -4sinx - x. So now just plug in the x-coordinate of your point.