anonymous
  • anonymous
Question 15 (Multiple Choice Worth 5 points) [9.05] Solve 3x2 + 5x + 7 = 0. Round solutions to the nearest hundredth. No real solutions x ≈ −6.34 and x ≈ 1.34 x ≈ −0.45 and x ≈ 2.11 x ≈ −2.11 and x ≈ 0.45
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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rob1525
  • rob1525
hi felicia123...at it again hu? lol! Okay, so u can use the pathagoriean therom again to find the x intercepts...remember its\[(-b + or - \sqrt{b^2-4*a*c})/2a\]
rob1525
  • rob1525
\[x1= (b + \sqrt{b^2-4*a*c})/2a\] and \[x2= (b - \sqrt{b^2-4*a*c})/2a\]
rob1525
  • rob1525
remember that a quadratic has the form a^2+b+c=0

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anonymous
  • anonymous
can you just tell me how to do this in the cal
rob1525
  • rob1525
okay a=3, b=5 and c=7.... :)
anonymous
  • anonymous
Is it A
rob1525
  • rob1525
idk
anonymous
  • anonymous
i think its a because of the 0
rob1525
  • rob1525
\[x1= (5 + \sqrt{5^2-4*3*7})/2a\]
anonymous
  • anonymous
it be 3x ^2-5x+7 =0
rob1525
  • rob1525
so b= -5
rob1525
  • rob1525
put -5 for b in the formula
anonymous
  • anonymous
-5
rob1525
  • rob1525
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anonymous
  • anonymous
oh ok
rob1525
  • rob1525
a=3, b=-5, and c=7 now put those values into this formula\[x1= (b + \sqrt{b^2-4*a*c})/2a\]
rob1525
  • rob1525
your original problem had + 5x and now u changed it to - 5x right?
anonymous
  • anonymous
yea
rob1525
  • rob1525
I have to get off now do u understand what u need to do?
anonymous
  • anonymous
some what but thanks
rob1525
  • rob1525
break it up into parts find what \[-5^2-4*3*7=?\] then square root it. Now it \[x = -5 + \sqrt{the value u got}\] then divide by 2*3...like the other problem we did. YOU CAN DO IT.. ;)

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