anonymous
  • anonymous
2x^3+6x^2+5/3+x^2 lim x to infinity
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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katieb
  • katieb
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anonymous
  • anonymous
Divide everything by the highest degree variable in the denominator. In this case it is \(x^2\):\[ \lim_{x\to \infty}\frac{2x^3+6x^2+5}{3+x^2} = \lim_{x\to \infty}\frac{2x+6+\frac{5}{x^2}}{\frac{3}{x^2}+1} \]
anonymous
  • anonymous
At this point you can plug in \(\infty\) and you will not have an indeterminate form.
anonymous
  • anonymous
wouldn't the highest degree be x^3? or does the numerator not count

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