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if AB=BA = I, then we can say B is the multiplicative inverse of A
so, lets find AB, and BA and see if we get I
A. B = A-1 B. B ≠ A-1
take 2 of those column
5*2 = 10 3*2 = 6
take -3 of that column and ADD
3*-3 = -9 2*-3 = -6
add them 10 + -9 = 1 6 + -6 = 0
yep thats what i got
keep that aside. we have one more column waiting to be multiplied, lets do that first
take -3 of those column
okay now how do we do that
Now perform the ADDition
1 0 0 1
Yes ! we got an Identity matrix !!! so we have half hope that B can be multiplicative inverse of A
we just got AB = I
so it'd be A (:?
we still beed to do BA and, IF we get BA = I aswell, then we can conclude !
okay how do we do that?
it would be 1?
Can you find BA, carry the exact same steps when we did AB
well first i got 10 & -15
second i got -9 & 15
perfect ! save it :) do it later Im sure u can do BA by now when u multiply BA, u wud get 1 0 0 1
so, BA also gives us identity ! that means A and B are inverses of eachother
alright than what im confused now
now, wat are the options we have ?
wouldnt it be 1*1 and 0*0"?
I am asking u to stop doing it for now :) i already did BA and got Identity matrix
please do it later ok :)
im confused im so sorry!
these are the only optiosn ? A. B = A-1 B. B ≠ A-1
B is incorrect
so well i think its a
yes A is correct ! but where are the other options ?
thats the only 2 options!! its just asking determine wheather B is the multiplicative inverse of A. So it has to be A.
Yep ! we should have stopped right after doing AB i got confused, i thought it is asking to do tell whether A is inverse of B aswell o.o
oh lol im sorry!
noo its okay :) good work ! i can see you're getting comfortable wid matrix multiplications so fast !!! actually these things confuse many ppl in the begining