anonymous
  • anonymous
Factor: c2 - d2 Answer (c + d)(c - d) (c + d)(c + d) (c + 2d)(c - d)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Difference of squares!
anonymous
  • anonymous
\[ a^2-b^2=(a-b)(a+b) \]
Yttrium
  • Yttrium
It's factors are sum and difference of binomials. :)

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More answers

anonymous
  • anonymous
Medal
anonymous
  • anonymous
its A .
uri
  • uri
c(c)-d(d) (c-d)(c+d)
uri
  • uri
or (c+d)(c-d)
anonymous
  • anonymous
@uri:your answer is true but how can we have (c-d)(c+d) from c(c)-d(d) ? can u prove it ?:)
anonymous
  • anonymous
Distributive property of multiplication over addition.\[ \huge QED \]
uri
  • uri
Well, c(c)-d(d) = (c+d)(c-d) or (c-d)(c+d)
anonymous
  • anonymous
Well, c(c)-d(d) = (c+d)(c-d) or (c-d)(c+d)
anonymous
  • anonymous
Distributive property of multiplication over addition. QED
anonymous
  • anonymous
@uri : :) I wanted prove not answer again :)
anonymous
  • anonymous
No problem :) Thank u :)
anonymous
  • anonymous
\[\begin{split} c(c)-d(d) &=c(c)-d(d)+0 \\ &=c(c)-d(d)+(cd-dc) \\ &=c(c)-d(d)+c(d)-d(c) \\ &=c(c)+c(d)-d(d)-d(c) \\ &=[c(c)+c(d)]-[d(d)+d(c)] \\ &=c(c+d)-d(d+c) \\ &=(c-d)(c+d) \\ \end{split} \]
anonymous
  • anonymous
@E.ali Medal, now.
uri
  • uri
medal me.kthxbye.
anonymous
  • anonymous
i dont know who i should give medal too o.O
anonymous
  • anonymous
To me. Please
uri
  • uri
To me duh.I gave the ansur first.
uri
  • uri
Also,I'm a pretty girl.
anonymous
  • anonymous
ali gave me first answer :D
uri
  • uri
Whose the prettiest gets the medal.
anonymous
  • anonymous
i dont see ur picture D:
uri
  • uri
Eli didn't even explain you xD
anonymous
  • anonymous
ahahahaha :D
uri
  • uri
Be like dat.Uri won't half ya with ansurs again.
DebbieG
  • DebbieG
Nobody should get a medal for giving the ANSWER. The medal should go to the person who explained/taught HOW to answer it. (Even if begging for a medal is pretty pathetic.)
anonymous
  • anonymous
uri, u give to ali then, and i give u :D
uri
  • uri
ANSUR* @DebbieG
anonymous
  • anonymous
lololol

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