anonymous
  • anonymous
There are 10 blue balls, 7 red balls, 14 green balls, 12 yellow balls, 9 black balls and 1 purple ball inside a bag. What is the minimum number of balls that must be drawn to ensure that at least one triplet of balls (three balls of same colour) is definitely present among the balls chosen?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
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anonymous
  • anonymous
there's a total of 53 balls. 53/3? I don't know if that's the step but the result is 17 so a 17/53 chance?
anonymous
  • anonymous
i didnt get that answer
anonymous
  • anonymous
Well, considering I probably did another method than what you did, tell me what answer you got and how

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More answers

anonymous
  • anonymous
28.345 something
anonymous
  • anonymous
total-23726,atleast three balls of same colour right
anonymous
  • anonymous
what the hell? why would you do 3-23726? where the hell did you get 23726 from??
anonymous
  • anonymous
please give respect while answering
anonymous
  • anonymous
I'm not disrespecting you, I asked a question
anonymous
  • anonymous
53C3-23726
anonymous
  • anonymous
53*52*51/3*2
anonymous
  • anonymous
53C3? Huh?
anonymous
  • anonymous
yes combinations
anonymous
  • anonymous
You have 10 + 7 +14 + 12 + 9 + 1 = 53 I don't know where you're getting this "combinations" from. Although, you seem to know how to work your own problem out.
anonymous
  • anonymous
out of 53 we are taking three balls
anonymous
  • anonymous
plse help me
anonymous
  • anonymous
There are balls of six different colours - blue, red, green, yellow, black and purple. There is a chance that the first three balls itself form a triplet. However, with three balls, one cannot ensure that a triplet is definitely formed. In the worst case, assume that the first six balls drawn are of different colours. Now, there are no purple balls left. So, the balls left are of five different colours. Again, if the next five balls that are drawn are of different colours, we definitely have two balls each of five colours and the solitary purple ball (when 11 balls have been drawn). All the other colours originally have more than two balls. So, the 12th ball that is drawn is definitely the third ball of any colour. Thus, a triplet can be ensured after at least 12 balls are drawn.
anonymous
  • anonymous
i cant understand please tell me
anonymous
  • anonymous
k i have understood @jibirajeev
anonymous
  • anonymous
first time we drawn 6 balls and then 5...so its 11... and in the next draw you need only onew ball to get a triplet .. so altogether...12
anonymous
  • anonymous
i am so weak in quants to understand this kind of problems .i am daily preparing maths.still i didnt get this type of questions
anonymous
  • anonymous
what to do
anonymous
  • anonymous
Practice....practice...

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