anonymous
  • anonymous
Is x^3 + x^3 + x^3 + x^3 the same as x^(3 + 3 + 3 + 3)?
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
They both equal x^12 so I'm thinking yeah
anonymous
  • anonymous
no
anonymous
  • anonymous
no,I don't think so...

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anonymous
  • anonymous
x^3 + x^3 + x^3 + x^3 = 4x^3
anonymous
  • anonymous
@UditKulka @PFEH.1999 How are they NOT the same when they equal the same? ._.
anonymous
  • anonymous
sorry, the first one is supposed to be multiplication, not addition. In that case, they are both x^12
Yttrium
  • Yttrium
They are not the same. No, they aren't both raise to 12.
anonymous
  • anonymous
Yes, they are.........
Yttrium
  • Yttrium
Ahhhh, well they are now the same. :) HAHAHA.
Yttrium
  • Yttrium
I thought it is plus.
anonymous
  • anonymous
>_> Can those be reduced further? I don't know how if so. Yeah, I copied and pasted the problem but it turned it into addition. idk how
anonymous
  • anonymous
simplified, rather. this is my question: http://i1341.photobucket.com/albums/o749/whalexnuker/untitled_zps0ddf0ea7.png
anonymous
  • anonymous
if it is multiplication it is
anonymous
  • anonymous
It is what? I asked if it could be simplified any further. Can it be?
anonymous
  • anonymous
no it can't be simplified
anonymous
  • anonymous
If it could, how would I be able to tell? (I have more problems like this to solve)
anonymous
  • anonymous
what u would be able to tell
anonymous
  • anonymous
i think you are totally confused
Yttrium
  • Yttrium
Yes is the answer for the first question since it will arrive at x^12. But in the Second (addition) it will absolutely not applicable. Because that adding of exponents is only applicable in multiplication of same base. (You see they are all the same x that is why you can add all of the exponent) But in addition, if you have same term, what you can only do is to add the coefficient. Since they are all x^3 you can add them up. Arriving at 4x3. Do you understand me? Sorry for very long answer.

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