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AllieEllenAllen
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What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slopeintercept form?
 one year ago
 one year ago
AllieEllenAllen Group Title
What is the equation of the line passing through (–6, 1) and perpendicular to the line y = –3x + 1 in slopeintercept form?
 one year ago
 one year ago

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goformit100 Group TitleBest ResponseYou've already chosen the best response.1
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 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Hi? Are you there?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Here will be references for you: You need to know slopeintercept form. It is that one form where you can easily see slope and \(y\)intercept. It is \(y=mx+b\) where \(m\) is the slope and \(b\) is the \(y\)intercept. A line that is perpendicular to another line has a negative reciprocal slope of the other. How do you know the slope of the other? It is in slopeintercept form, so you can look at what must be \(m\); what is multiplying \(x\). So, you can find your slope that way. Then you can use pointslope formula, \(\dfrac{yy_1}{xx_1}=m\). You know that your point on the line is \((x_1,\ y_1)\) and you know the slope, \(m\), from finding the negative reciprocal of the other slope. Then solve for \(y\) in that last equation to see the slopeintercept form.
 one year ago
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