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C. try substituting the values in option C
okay what about solve the system using elimination 2x+6y=-12 5x-5y=10 choices A.(2,1) B.(0,-2) C.(-2,0) D.(1,2)
For elimination methosd, 2x+6y=-12 ---> (1) 5x-5y=10 --->(2) Let's make both eqn (1) and eqn (2) have 10x in them. to do so, multiply. So for (1), multiply by 5. it'll become 10x+30y=-60 ---> (3) for (2), multiply by 2. it'll become 10x-10y=20 --->(4)
Then to eliminate 10x, take (3)-(4) so, 10x+30y-(10x-10y) = -60 - 20 40y=-80 y=-2 :) then sub y=-2 into (1) 2x+6(-2)=-12 2x=0 x=0 :)
do u understand?
okay so you jus make both equations have a common number in them
yes that's right
i was watching , i would like to comment on the first problem "solve using substitution.
what about it?
you do not just substitute given answers to see if it satisfies the equation you do it like this 2x+y=-11 3x-4y=11 first solve for a variable , y would be easiest because it is by itself in equation 1 y= -11 -2x subtracted 2x from both sides and then substitute that in for y in the 2nd equation like so: 3x- 4( -11 -2x) =11 and then solve
once you get an answer for x plug that back in to get y and do not forget to do your checks
do you mulitply -4 and -11 and -4 and -2x?
okay so you get 3x-44-8x=11 do you combine like terms (the 3x and -8x)
-4 times -2x is positive
3x and 8x pay careful attention to your signs
so now i have 11x+44=11 subtract 44 from both sides and get 11x=-33
divide both sides by 11 to isolate x
so the anwser is C
yes take that and plug it in on of the equations and solve for y
alright thanks for your help
yes good job!!!! remember to plug your x and y values in both equations as a check