anonymous
  • anonymous
Find part "b". https://media.glynlyon.com/g_geo_2013/5/01.gif Math please help
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
i says the answer is something like this blank=4blank/blank
anonymous
  • anonymous
\[\frac{ x }{ 15 }=\sin 30=\frac{ 1 }{ 2 },x=\frac{ 15 }{ 2 },\]
anonymous
  • anonymous
im confused >.<

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anonymous
  • anonymous
how?
anonymous
  • anonymous
b=4blank/blank but there was no 4
anonymous
  • anonymous
|dw:1378916482495:dw|
anonymous
  • anonymous
this https://media.glynlyon.com/g_geo_2013/5/01.gif
anonymous
  • anonymous
wait i have not completed the question. first find x as i have found. then y from smaller two triangles then equate y to find b
anonymous
  • anonymous
you may also find z by pythagoras theorem sides are 15 and 15/2
anonymous
  • anonymous
find z, i will see your work.
anonymous
  • anonymous
15^2+15/2^2 = 1125/4 or 281.25
anonymous
  • anonymous
right?
anonymous
  • anonymous
\[z=\sqrt{\left( 15 \right)^{2}-\left( \frac{ 15 }{ 2 } \right)^{2}}=15\sqrt{1-\frac{ 1 }{4 }}=\frac{ 15\sqrt{3} }{2}\]
anonymous
  • anonymous
\[\frac{ b }{z }=\cos 30=\frac{ 1 }{ 2 },b=\frac{ z }{ 2 }=\frac{ 15\sqrt{3} }{4 }\]
anonymous
  • anonymous
|dw:1378917463146:dw|
anonymous
  • anonymous
correction write 15/2 in place of 4 in the diagram.
anonymous
  • anonymous
you have to find x first. if you have any doubt you can ask me.
anonymous
  • anonymous
i cant replace the 4 tho its fill in the blank on my online class
anonymous
  • anonymous
one more correction \[ \cos 30=\frac{ \sqrt{3} }{2 }\]
anonymous
  • anonymous
\[b=\frac{ 15\sqrt{3} }{ 2 }*\frac{ \sqrt{3} }{ 2 }=\frac{ 45 }{4 }\]
anonymous
  • anonymous
:D
anonymous
  • anonymous
you can solve this question by many ways e.g., similarity of triangles.
anonymous
  • anonymous
thank you so much !
anonymous
  • anonymous
yw

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