anonymous
  • anonymous
Find the distance between the two points. Round to the nearest tenth if necessary. (–4, –12), (11, –6)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
jdoe0001
  • jdoe0001
\(\bf \text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\)
anonymous
  • anonymous
|dw:1378921561152:dw|
anonymous
  • anonymous
is this right so far?

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
sorry its a bit sloppy but hope you can read that
jdoe0001
  • jdoe0001
well, you have -6 twice in the root, for the "x" part and for the "y" part, so, you kinda skipped the " 11 " there
anonymous
  • anonymous
11? im confused... can you show me how you do this? :(
anonymous
  • anonymous
oh wait nvm i got ya.. idk why i forgot the 11!
anonymous
  • anonymous
i did it completely wrong lol
jdoe0001
  • jdoe0001
\(\large \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ (&–4, &–12), (&11,& –6) \end{array}\)
jdoe0001
  • jdoe0001
either point can be first or second btw
anonymous
  • anonymous
|dw:1378922114764:dw|
anonymous
  • anonymous
thats all i did so far.. what do i do next?
anonymous
  • anonymous
oh okay :)
jdoe0001
  • jdoe0001
\(\bf (11, –6),(–4, –12) \\ \text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\\quad \\ d = \sqrt{((-4)-(11))^2 + ((-12)-(-6))^2}\\\quad \\ d = \sqrt{(-15)^2+(-6)^2} \implies \sqrt{261} \)
anonymous
  • anonymous
a. 19.3 b. 21 c. 16.2 d. 261 howd you get 261?
jdoe0001
  • jdoe0001
|dw:1378922797390:dw| \(\bf (11, –6),(–4, –12) \\ \text{distance between 2 points}\\ d = \sqrt{(x_2-x_1)^2 + (y_2-y_1)^2}\\\quad \\ d = \sqrt{((-4)-(11))^2 + ((-12)-(-6))^2}\\\quad \\\quad \\ d = \sqrt{(-15)^2+(-6)^2} \implies \sqrt{225+36} \implies \sqrt{261}\\ -------------------\\ \color{green}{261 = 3 \times 3 \times 29 \implies 3^2 \times 29}\\ -------------------\\ \sqrt{225+36} \implies \sqrt{3^2 \times 29} \implies 3\sqrt{29}\)
jdoe0001
  • jdoe0001
or \(\bf \sqrt{261} \implies \sqrt{3^2 \times 29} \implies 3\sqrt{29}\) for that matter
jdoe0001
  • jdoe0001
and it seems your choices are all decimals, so just multiply the 3 times that to get your decimal value
anonymous
  • anonymous
oh okay i get what you did but idk what are you doing when you put 261=3x3x29---> 3^2x29?
jdoe0001
  • jdoe0001
so-called "simplifying the number" that is, breaking it in factors
anonymous
  • anonymous
oh okay i see now. thank you so much. so my answer is 261 :)?
jdoe0001
  • jdoe0001
for your case, this time, it doesn't matter because your choices are in decimal, and you don't need the factored version
jdoe0001
  • jdoe0001
well, not exactly 261, \(\bf \sqrt{261} \implies \sqrt{3^2 \times 29} \implies \large \color{blue}{3\sqrt{29}}\)
jdoe0001
  • jdoe0001
\(\bf 3\sqrt{29}\implies 3 \times \sqrt{29}\)
anonymous
  • anonymous
but thats not my answer choice lol. how do i convert that to a decimal?
jdoe0001
  • jdoe0001
\((\bf 3\sqrt{29}\implies \huge3 \times \sqrt{29}\)
jdoe0001
  • jdoe0001
what does that give you?
anonymous
  • anonymous
16.1
jdoe0001
  • jdoe0001
well, 16.15549442, which rounds up to 16.2
anonymous
  • anonymous
haha yeah that! thank youu.
jdoe0001
  • jdoe0001
yw

Looking for something else?

Not the answer you are looking for? Search for more explanations.