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djaydeej88 Group TitleBest ResponseYou've already chosen the best response.1
#1. Peter did not simplify his answer completely because he did not reach the conclusion of \[x ^{12}\] second part of the problem is that \[x^3 x^3 x^3 x^3 \neq x^3 + x^3 + x^3 + x^3\] so Peter's work would NOT be the same.
 one year ago

djaydeej88 Group TitleBest ResponseYou've already chosen the best response.1
\[x^3 + x^3 + x^3 + x^3 = 4x^3\]
 one year ago

djaydeej88 Group TitleBest ResponseYou've already chosen the best response.1
#2. use property of negative exponents in addition to fractional exponents. #3. use quotient property since the base is the same.
 one year ago

djaydeej88 Group TitleBest ResponseYou've already chosen the best response.1
#4.\[\sqrt[3]{x^3} = x ^{3*(1/3)}\] involves powers of a product \[x ^{1/3}x ^{1/3}x ^{1/3} = x ^{(1/3) + (1/3) + (1/3)} = x ^{3/3} = x\] involves product of powers \[1/x ^{1} = x ^{1} = x\] involves negative exponents
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
Could you help me on showing my work for #2 and #3 ? I don't even know where to begin ..
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[\sqrt[n]{x}=\left( x \right)^{\frac{ 1 }{n }}\]
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 1 }{\sqrt[3]{x ^{6}} }=\frac{ 1 }{\left( x ^{6} \right)^{\frac{ 1 }{3 }} }=\frac{ 1 }{\left( x \right)^{6*\frac{ 1 }{ 3 }} } =\frac{ 1 }{ x ^{2 } } =x ^{2}\] i think i have cleared everything,if any doubt ask me.
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
I'm starting to understand
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
Would number 3 be dw:1378942627571:dw ??
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ x ^{\frac{ 2 }{ 3 }} }{ x ^{\frac{ 4 }{9 }} }=x ^{\frac{ 2 }{3 }}*x ^{\frac{ 4 }{9 }}\] \[=x ^{\left( \frac{ 2 }{ 3 }\frac{ 4 }{9 } \right)}\] take L.C.M and solve.
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
when bases are same powers are added during multiplication.
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
Okay no I don't get it ..... None of this makes sense :( What's being added and what's being multiplied here ?
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[x ^{a}*x ^{b}=x ^{a+b}\]
 one year ago

djaydeej88 Group TitleBest ResponseYou've already chosen the best response.1
for #3, when you have the same bases, and it is a division problem, the powers are subtracted. the power from the denominator is subtracted from the power in the numerator like so \[x ^{2/3}/x ^{4/9} = x ^{(2/3)(4/9)}\]
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 2 }{3 }and \frac{ 4 }{ 9 } are added\]
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
I would be able to figure that out if I could find my freaking scientific calculator :'c
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{ 2 }{3 }and \frac{ 4 }{ 9 } are added\]
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
\[yes x ^{\frac{ 2 }{ 9 }}\]
 one year ago

djaydeej88 Group TitleBest ResponseYou've already chosen the best response.1
use this property when you see a problem like #3 \[x ^{m}/x ^{n} = x ^{mn}\]
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
So is 2/9 the answer then ? :o
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
Okay thank you so much
 one year ago

surjithayer Group TitleBest ResponseYou've already chosen the best response.0
note that answer is not 2/9 it is as i have given above x ^2/9
 one year ago

LaynaMae Group TitleBest ResponseYou've already chosen the best response.0
Ohh okay well that makes more sense now . Thank YOU
 one year ago
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