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anonymous
 2 years ago
Helpp ?
anonymous
 2 years ago
Helpp ?

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anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0#1. Peter did not simplify his answer completely because he did not reach the conclusion of \[x ^{12}\] second part of the problem is that \[x^3 x^3 x^3 x^3 \neq x^3 + x^3 + x^3 + x^3\] so Peter's work would NOT be the same.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[x^3 + x^3 + x^3 + x^3 = 4x^3\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0#2. use property of negative exponents in addition to fractional exponents. #3. use quotient property since the base is the same.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0#4.\[\sqrt[3]{x^3} = x ^{3*(1/3)}\] involves powers of a product \[x ^{1/3}x ^{1/3}x ^{1/3} = x ^{(1/3) + (1/3) + (1/3)} = x ^{3/3} = x\] involves product of powers \[1/x ^{1} = x ^{1} = x\] involves negative exponents

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Could you help me on showing my work for #2 and #3 ? I don't even know where to begin ..

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\sqrt[n]{x}=\left( x \right)^{\frac{ 1 }{n }}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 1 }{\sqrt[3]{x ^{6}} }=\frac{ 1 }{\left( x ^{6} \right)^{\frac{ 1 }{3 }} }=\frac{ 1 }{\left( x \right)^{6*\frac{ 1 }{ 3 }} } =\frac{ 1 }{ x ^{2 } } =x ^{2}\] i think i have cleared everything,if any doubt ask me.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I'm starting to understand

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Would number 3 be dw:1378942627571:dw ??

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ x ^{\frac{ 2 }{ 3 }} }{ x ^{\frac{ 4 }{9 }} }=x ^{\frac{ 2 }{3 }}*x ^{\frac{ 4 }{9 }}\] \[=x ^{\left( \frac{ 2 }{ 3 }\frac{ 4 }{9 } \right)}\] take L.C.M and solve.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0when bases are same powers are added during multiplication.

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay no I don't get it ..... None of this makes sense :( What's being added and what's being multiplied here ?

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[x ^{a}*x ^{b}=x ^{a+b}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0for #3, when you have the same bases, and it is a division problem, the powers are subtracted. the power from the denominator is subtracted from the power in the numerator like so \[x ^{2/3}/x ^{4/9} = x ^{(2/3)(4/9)}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2 }{3 }and \frac{ 4 }{ 9 } are added\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0I would be able to figure that out if I could find my freaking scientific calculator :'c

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 2 }{3 }and \frac{ 4 }{ 9 } are added\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0\[yes x ^{\frac{ 2 }{ 9 }}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0use this property when you see a problem like #3 \[x ^{m}/x ^{n} = x ^{mn}\]

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0So is 2/9 the answer then ? :o

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Okay thank you so much

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0note that answer is not 2/9 it is as i have given above x ^2/9

anonymous
 2 years ago
Best ResponseYou've already chosen the best response.0Ohh okay well that makes more sense now . Thank YOU
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