## theEric one year ago Hi! I am solving a problem, and I think I correctly arrived at $$\ln\left|e^y-2x\ y\right|=C$$. At any rate, I think I'll be left with $$\ln\left|e^y-2x\ y\right|$$, and I don't know how to solve for $$y$$!

1. theEric

What I have done is this:

2. theEric

Put each side as the exponent of $$e$$. Then $$e^{\ln\left|e^y-2x\ y\right|}=e^C\\\implies e^y-2x\ y=C$$ where $$C$$ is still just an arbitrary constant.

3. myko

Let me guess, you solving a ODE? Not always it is posible to explicitly express y as function of x. Sometimes you just leave a general solution in implicit form

4. theEric

This is from an ODE.... I am supposed to solve it implicitly. Have I done that, then?

5. theEric

Assuming I got there correctly, I mean. I don't want to ask you to check my work.

6. myko

yes, you are done

7. theEric

Thank you! :)

8. myko

yw