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Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
 7 months ago
 7 months ago
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
 7 months ago
 7 months ago

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theEricBest ResponseYou've already chosen the best response.0
What I have done is this:
 7 months ago

theEricBest ResponseYou've already chosen the best response.0
Put each side as the exponent of \(e\). Then \(e^{\ln\lefte^y2x\ y\right}=e^C\\\implies e^y2x\ y=C\) where \(C\) is still just an arbitrary constant.
 7 months ago

mykoBest ResponseYou've already chosen the best response.1
Let me guess, you solving a ODE? Not always it is posible to explicitly express y as function of x. Sometimes you just leave a general solution in implicit form
 7 months ago

theEricBest ResponseYou've already chosen the best response.0
This is from an ODE.... I am supposed to solve it implicitly. Have I done that, then?
 7 months ago

theEricBest ResponseYou've already chosen the best response.0
Assuming I got there correctly, I mean. I don't want to ask you to check my work.
 7 months ago
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