A community for students.
Here's the question you clicked on:
 0 viewing
theEric
 one year ago
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
theEric
 one year ago
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!

This Question is Closed

theEric
 one year ago
Best ResponseYou've already chosen the best response.0What I have done is this:

theEric
 one year ago
Best ResponseYou've already chosen the best response.0Put each side as the exponent of \(e\). Then \(e^{\ln\lefte^y2x\ y\right}=e^C\\\implies e^y2x\ y=C\) where \(C\) is still just an arbitrary constant.

myko
 one year ago
Best ResponseYou've already chosen the best response.1Let me guess, you solving a ODE? Not always it is posible to explicitly express y as function of x. Sometimes you just leave a general solution in implicit form

theEric
 one year ago
Best ResponseYou've already chosen the best response.0This is from an ODE.... I am supposed to solve it implicitly. Have I done that, then?

theEric
 one year ago
Best ResponseYou've already chosen the best response.0Assuming I got there correctly, I mean. I don't want to ask you to check my work.
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.