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theEric
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Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
 one year ago
 one year ago
theEric Group Title
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
 one year ago
 one year ago

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theEric Group TitleBest ResponseYou've already chosen the best response.0
What I have done is this:
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Put each side as the exponent of \(e\). Then \(e^{\ln\lefte^y2x\ y\right}=e^C\\\implies e^y2x\ y=C\) where \(C\) is still just an arbitrary constant.
 one year ago

myko Group TitleBest ResponseYou've already chosen the best response.1
Let me guess, you solving a ODE? Not always it is posible to explicitly express y as function of x. Sometimes you just leave a general solution in implicit form
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
This is from an ODE.... I am supposed to solve it implicitly. Have I done that, then?
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Assuming I got there correctly, I mean. I don't want to ask you to check my work.
 one year ago

myko Group TitleBest ResponseYou've already chosen the best response.1
yes, you are done
 one year ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Thank you! :)
 one year ago
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