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theEric
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Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
 10 months ago
 10 months ago
theEric Group Title
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
 10 months ago
 10 months ago

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theEric Group TitleBest ResponseYou've already chosen the best response.0
What I have done is this:
 10 months ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Put each side as the exponent of \(e\). Then \(e^{\ln\lefte^y2x\ y\right}=e^C\\\implies e^y2x\ y=C\) where \(C\) is still just an arbitrary constant.
 10 months ago

myko Group TitleBest ResponseYou've already chosen the best response.1
Let me guess, you solving a ODE? Not always it is posible to explicitly express y as function of x. Sometimes you just leave a general solution in implicit form
 10 months ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
This is from an ODE.... I am supposed to solve it implicitly. Have I done that, then?
 10 months ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Assuming I got there correctly, I mean. I don't want to ask you to check my work.
 10 months ago

myko Group TitleBest ResponseYou've already chosen the best response.1
yes, you are done
 10 months ago

theEric Group TitleBest ResponseYou've already chosen the best response.0
Thank you! :)
 10 months ago
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