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theEric
 2 years ago
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!
theEric
 2 years ago
Hi! I am solving a problem, and I think I correctly arrived at \(\ln\lefte^y2x\ y\right=C\). At any rate, I think I'll be left with \(\ln\lefte^y2x\ y\right\), and I don't know how to solve for \(y\)!

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theEric
 2 years ago
Best ResponseYou've already chosen the best response.0What I have done is this:

theEric
 2 years ago
Best ResponseYou've already chosen the best response.0Put each side as the exponent of \(e\). Then \(e^{\ln\lefte^y2x\ y\right}=e^C\\\implies e^y2x\ y=C\) where \(C\) is still just an arbitrary constant.

myko
 2 years ago
Best ResponseYou've already chosen the best response.1Let me guess, you solving a ODE? Not always it is posible to explicitly express y as function of x. Sometimes you just leave a general solution in implicit form

theEric
 2 years ago
Best ResponseYou've already chosen the best response.0This is from an ODE.... I am supposed to solve it implicitly. Have I done that, then?

theEric
 2 years ago
Best ResponseYou've already chosen the best response.0Assuming I got there correctly, I mean. I don't want to ask you to check my work.
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