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ArTFis
 3 years ago
Where and how do you start such a long factoring problem?
3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
ArTFis
 3 years ago
Where and how do you start such a long factoring problem? 3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2

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ArTFis
 3 years ago
Best ResponseYou've already chosen the best response.0This problem is only to FACTOR

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0note that (2x1)^2 is a common factor of the 2 terms so that can be taken out also we can take out (1/2) (x+3)^1/2 ope that helps

ArTFis
 3 years ago
Best ResponseYou've already chosen the best response.0Alright. It does help. Thank you very much!

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0the first line of your answer is (2x1)^2 (1/2)(x + 3)^1/2 [ 3*(4x + 3) + (2x1)]

cwrw238
 3 years ago
Best ResponseYou've already chosen the best response.0now it only remains to simplify whats in the parentheses
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