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ArTFis
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Where and how do you start such a long factoring problem?
3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
 10 months ago
 10 months ago
ArTFis Group Title
Where and how do you start such a long factoring problem? 3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
 10 months ago
 10 months ago

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ArTFis Group TitleBest ResponseYou've already chosen the best response.0
This problem is only to FACTOR
 10 months ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
note that (2x1)^2 is a common factor of the 2 terms so that can be taken out also we can take out (1/2) (x+3)^1/2 ope that helps
 10 months ago

ArTFis Group TitleBest ResponseYou've already chosen the best response.0
Alright. It does help. Thank you very much!
 10 months ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
the first line of your answer is (2x1)^2 (1/2)(x + 3)^1/2 [ 3*(4x + 3) + (2x1)]
 10 months ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
now it only remains to simplify whats in the parentheses
 10 months ago
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