Where and how do you start such a long factoring problem? 3(2x-1)^2 (2)(x+3)^1/2 + (2x-1)^3 (1/2)(x+3)^-1/2

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Where and how do you start such a long factoring problem? 3(2x-1)^2 (2)(x+3)^1/2 + (2x-1)^3 (1/2)(x+3)^-1/2

Mathematics
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This problem is only to FACTOR
note that (2x-1)^2 is a common factor of the 2 terms so that can be taken out also we can take out (1/2) (x+3)^-1/2 ope that helps
Alright. It does help. Thank you very much!

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Other answers:

yw
the first line of your answer is (2x-1)^2 (1/2)(x + 3)^-1/2 [ 3*(4x + 3) + (2x-1)]
now it only remains to simplify whats in the parentheses

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