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ArTFis
 one year ago
Where and how do you start such a long factoring problem?
3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
ArTFis
 one year ago
Where and how do you start such a long factoring problem? 3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2

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ArTFis
 one year ago
Best ResponseYou've already chosen the best response.0This problem is only to FACTOR

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.0note that (2x1)^2 is a common factor of the 2 terms so that can be taken out also we can take out (1/2) (x+3)^1/2 ope that helps

ArTFis
 one year ago
Best ResponseYou've already chosen the best response.0Alright. It does help. Thank you very much!

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.0the first line of your answer is (2x1)^2 (1/2)(x + 3)^1/2 [ 3*(4x + 3) + (2x1)]

cwrw238
 one year ago
Best ResponseYou've already chosen the best response.0now it only remains to simplify whats in the parentheses
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