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ArTFis
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Where and how do you start such a long factoring problem?
3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
 one year ago
 one year ago
ArTFis Group Title
Where and how do you start such a long factoring problem? 3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
 one year ago
 one year ago

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ArTFis Group TitleBest ResponseYou've already chosen the best response.0
This problem is only to FACTOR
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
note that (2x1)^2 is a common factor of the 2 terms so that can be taken out also we can take out (1/2) (x+3)^1/2 ope that helps
 one year ago

ArTFis Group TitleBest ResponseYou've already chosen the best response.0
Alright. It does help. Thank you very much!
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
the first line of your answer is (2x1)^2 (1/2)(x + 3)^1/2 [ 3*(4x + 3) + (2x1)]
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.0
now it only remains to simplify whats in the parentheses
 one year ago
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