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Where and how do you start such a long factoring problem?
3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
 7 months ago
 7 months ago
Where and how do you start such a long factoring problem? 3(2x1)^2 (2)(x+3)^1/2 + (2x1)^3 (1/2)(x+3)^1/2
 7 months ago
 7 months ago

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ArTFisBest ResponseYou've already chosen the best response.0
This problem is only to FACTOR
 7 months ago

cwrw238Best ResponseYou've already chosen the best response.0
note that (2x1)^2 is a common factor of the 2 terms so that can be taken out also we can take out (1/2) (x+3)^1/2 ope that helps
 7 months ago

ArTFisBest ResponseYou've already chosen the best response.0
Alright. It does help. Thank you very much!
 7 months ago

cwrw238Best ResponseYou've already chosen the best response.0
the first line of your answer is (2x1)^2 (1/2)(x + 3)^1/2 [ 3*(4x + 3) + (2x1)]
 7 months ago

cwrw238Best ResponseYou've already chosen the best response.0
now it only remains to simplify whats in the parentheses
 7 months ago
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