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Emineyy
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A dragster travels 1/4 mi in 6.7 s. Assuming that acceleration is constant and the dragster is initially at rest, what is its velocity when it crosses the finish line?
Please show step by step...
 one year ago
 one year ago
Emineyy Group Title
A dragster travels 1/4 mi in 6.7 s. Assuming that acceleration is constant and the dragster is initially at rest, what is its velocity when it crosses the finish line? Please show step by step...
 one year ago
 one year ago

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campbell_st Group TitleBest ResponseYou've already chosen the best response.0
so use \[average ..speed = \frac{distance..travelled}{time..taken}\]
 one year ago

Emineyy Group TitleBest ResponseYou've already chosen the best response.0
I tried but my answer was wrong.) I got 267 mi/h??
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
did you try feet/sec..?
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
and I think your answer is incorrect for the right formula
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
1/4 mile = 5280/4 = 1320 ft avg speed 1320/6.7 = ...
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
even using 0.25/6.7 will give miles/sec then multiply by 60 to get miles/min then multiply by 60 to get miles/hr
 one year ago

Emineyy Group TitleBest ResponseYou've already chosen the best response.0
the answer is given it's 269 mi/h ???
 one year ago

campbell_st Group TitleBest ResponseYou've already chosen the best response.0
wow...
 one year ago
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