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Given F1=2xi2yzjy^2k and F2=yixj,
Are these forces conservative?
 7 months ago
 7 months ago
Given F1=2xi2yzjy^2k and F2=yixj, Are these forces conservative?
 7 months ago
 7 months ago

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RequiemBest ResponseYou've already chosen the best response.0
I want to use the method of curl F, where the operator multiplied by F would tell me if it is conservative IF it equals 0
 7 months ago

ybarrapBest ResponseYou've already chosen the best response.0
$$ if~ g(x,y,z)=x^2y^2zy^3/3\\ then ~\nabla g=F_1 $$ So F1 is conservative. For F2: $$ \partial M/\partial y=1\\ \partial N/\partial x=1 $$ Since these are not equal, F2 is not conserviative.
 7 months ago

RequiemBest ResponseYou've already chosen the best response.0
I need those steps broken down alittle more please if you can
 7 months ago

sara17Best ResponseYou've already chosen the best response.0
you should take curl of those force f1 is concerviative because: ((d/dy)(y^2)(d/dz)(2yz))i+((d/dz)(2x)(d/dx)(y^2))j+((d/dx)(2yz)(d/dy)(2x))k 2y+2y+0+0=0 so f1 is concervative
 7 months ago

sara17Best ResponseYou've already chosen the best response.0
but f2 is not concervative because curl f2=2
 7 months ago
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