## anonymous 3 years ago a machine can toss a golf ball a distance of 120 m on a level playing field when the machine is set to an angle of 30 degrees. How far can the machine toss the ball when it is set to an angle of 45 degrees.

1. anonymous

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2. anonymous

ok so where do i go from there

3. anonymous

$R=\frac{u^2 \sin(2 \theta)}{g}$ $\theta = 30 degrees$R=120m $120=\frac{u^2 \sin(2 *30)}{10}$ find u.

4. anonymous

then find R for 45 degrees with this u.

5. anonymous

ok, so is it 170 m, 98 m , 140 m , 85 m or 150 m? trying to check my answer

6. anonymous

what u you got?

7. anonymous

98 m?

8. anonymous

$u^2 = \frac{120*10}{\sin 60}$ $u^2 = 800\sqrt{3}$ now theta = 45 $R=\frac{u^2 \sin(2*45)}{10}$ substitute value of u^2. $R=\frac{800 \sqrt{3} \sin(2*45)}{10}$

9. anonymous

$R=80\sqrt{3}$

10. anonymous

man i missed that up, so with sig figs.... 140 m?