## kbarnes7 Group Title a machine can toss a golf ball a distance of 120 m on a level playing field when the machine is set to an angle of 30 degrees. How far can the machine toss the ball when it is set to an angle of 45 degrees. 10 months ago 10 months ago

1. shubham.bagrecha Group Title

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2. kbarnes7 Group Title

ok so where do i go from there

3. shubham.bagrecha Group Title

$R=\frac{u^2 \sin(2 \theta)}{g}$ $\theta = 30 degrees$R=120m $120=\frac{u^2 \sin(2 *30)}{10}$ find u.

4. shubham.bagrecha Group Title

then find R for 45 degrees with this u.

5. kbarnes7 Group Title

ok, so is it 170 m, 98 m , 140 m , 85 m or 150 m? trying to check my answer

6. shubham.bagrecha Group Title

what u you got?

7. kbarnes7 Group Title

98 m?

8. shubham.bagrecha Group Title

$u^2 = \frac{120*10}{\sin 60}$ $u^2 = 800\sqrt{3}$ now theta = 45 $R=\frac{u^2 \sin(2*45)}{10}$ substitute value of u^2. $R=\frac{800 \sqrt{3} \sin(2*45)}{10}$

9. shubham.bagrecha Group Title

$R=80\sqrt{3}$

10. kbarnes7 Group Title

man i missed that up, so with sig figs.... 140 m?