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mathavraj

  • one year ago

how is the diode connected in the feedback path?

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  1. mathavraj
    • one year ago
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    |dw:1379408311303:dw|

  2. mathavraj
    • one year ago
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    @CarlosGP could u please explain this precision rectifier?

  3. mathavraj
    • one year ago
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    im confused about the diode voltage drop...

  4. mathavraj
    • one year ago
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    hmm..sorry a voltage supply is connected to the non inverting terminal

  5. mathavraj
    • one year ago
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    this is an inverting voltage follower..so the cathode would be at negative potential...is it correct?

  6. mathavraj
    • one year ago
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    http://en.wikipedia.org/wiki/File:Op-Amp_Precision_Rectifier.svg actually this is the circuit that i wanted to draw.

  7. mathavraj
    • one year ago
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    yeah..

  8. mathavraj
    • one year ago
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    by opamp output..you mean the terminal to which anode terminal of the diode is connected ..right?

  9. mathavraj
    • one year ago
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    you mean the load voltage will be the negative of Vin

  10. mathavraj
    • one year ago
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    but usually dont we write the output of the opamp at the feedback junction...i mean does it change?

  11. mathavraj
    • one year ago
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    ok..im just so confused with this,...damn

  12. mathavraj
    • one year ago
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    wow..thats a neat explanation..thanks...but i have one more small doubt...generally when we talk of opamps where is the output voltage( ie Vout=K(V+ -V-)) ...is it AT the feedback junction or BEFORE or AFTER it?

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