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how is the diode connected in the feedback path?

MIT 6.002 Circuits and Electronics, Spring 2007
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@CarlosGP could u please explain this precision rectifier?
im confused about the diode voltage drop...

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Other answers:

hmm..sorry a voltage supply is connected to the non inverting terminal
this is an inverting voltage follower..so the cathode would be at negative potential...is it correct?
http://en.wikipedia.org/wiki/File:Op-Amp_Precision_Rectifier.svg actually this is the circuit that i wanted to draw.
yeah..
by opamp output..you mean the terminal to which anode terminal of the diode is connected ..right?
you mean the load voltage will be the negative of Vin
but usually dont we write the output of the opamp at the feedback junction...i mean does it change?
ok..im just so confused with this,...damn
wow..thats a neat explanation..thanks...but i have one more small doubt...generally when we talk of opamps where is the output voltage( ie Vout=K(V+ -V-)) ...is it AT the feedback junction or BEFORE or AFTER it?

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