anonymous
  • anonymous
how is the diode connected in the feedback path?
MIT 6.002 Circuits and Electronics, Spring 2007
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
@CarlosGP could u please explain this precision rectifier?
anonymous
  • anonymous
im confused about the diode voltage drop...

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anonymous
  • anonymous
hmm..sorry a voltage supply is connected to the non inverting terminal
anonymous
  • anonymous
this is an inverting voltage follower..so the cathode would be at negative potential...is it correct?
anonymous
  • anonymous
http://en.wikipedia.org/wiki/File:Op-Amp_Precision_Rectifier.svg actually this is the circuit that i wanted to draw.
anonymous
  • anonymous
yeah..
anonymous
  • anonymous
by opamp output..you mean the terminal to which anode terminal of the diode is connected ..right?
anonymous
  • anonymous
you mean the load voltage will be the negative of Vin
anonymous
  • anonymous
but usually dont we write the output of the opamp at the feedback junction...i mean does it change?
anonymous
  • anonymous
ok..im just so confused with this,...damn
anonymous
  • anonymous
wow..thats a neat explanation..thanks...but i have one more small doubt...generally when we talk of opamps where is the output voltage( ie Vout=K(V+ -V-)) ...is it AT the feedback junction or BEFORE or AFTER it?

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