Write an equation for a line paralell to 6x-5y=15 and travels through the point (5,-2) ?
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When a line in form of "y = mx + c" has an another equation which is parallel to it
the gradient of both line should be equal
u have to find the gradient of the equation 6x - 5y = 15
let's say that value is "D"
then u can write another equation
Y = Dx + C
Now u can apply the given co-ordinates in the equation u formed and find C
Now write the full equation substituting that value
Y =Dx +c
and u will have ur answer
Can u do that ?
no im confused
@jim_thompson5910 mind helping me on this problem please?
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Have you ever plotted a graph?
Try to plot y = 2x + 1 and seeing what slope 2 means. For every 2 steps up you go one step right.
why would i plot y=2x+1?
Just a suggestion so you can understand the question. Math is not a spectator sport.
Do you see why y = 2x + 1 and y = 2x + 2 are parallel?
I hope u understand wt the gradient is ...
gradient is simply the slope of a straight line
when there r 2 lines which r parallel to each other this "slope" should be equal|dw:1379569731062:dw|
and the gradient of a function is represent by "m" in the form
Y = mx +c
In ur case
5y = 6x - 15
y = (6/5)x -3
so the gradient of the given line is 6/5
Now the equation of the other line also should contain the gradient 6/5
Y = mx + C
the equation asked in the problem should be somewhat like this
y =(6/5)x +C
here C represents the intercept of the graph
we can find out C by the given co-ordinate (5,-2)
i.e. if we substitute that values in the function y =(6/5)x +C
we get the function wr the given conditions r satisfied
-2 = 6 + c
c = -8
so the function of the line that passes through the point C
y = (6/5)x -8
hope this will help u out!