Here's the question you clicked on:
mikaa_toxica13
16 = -d + 6
I am not sure...I think it would still be 10...
But tha negative sign confuses.
No negative number plus six will get to sixteen.
transpose 6 to the other side so -6 + 16 = -d Add like terms 10 = -d d=-10 :)
thanks can u help with another ??
I might be able to.
b - 3 over -5 = -15
So is this what you are asking?:\[\frac{ b-3 }{ -5 }=-15\]
Okay, so really this is the same thing as being this:\[(b-3)\div-5=-15\]Now, like I said before - you have to work backwards. Do PEMDAS backwards. SADMEP. So if you do it correctly, it would come out b=78
ok can u explain the steps ?
This is what I did: (-15 * -5) + 3 = b = 78
Or, if you want to me to be more specific: (b - 3) / -5 = -15 (-15 * -5) + 3 = b 75 + 3 = b 78 = b
Thanks ! -10 = 5 + z over -5
\[-10=\frac{ 5+2 }{ 5 }\]\[-10=(5+2)\div5\]\[(-10\times5)-5\]\[-50-5\]\[z=-55\]
13 = -8p - 3 + 9p
I got 16, but based on my special calculator it is 4, so the answer is 4.
Can u explain the steps
I can't because when I tried to do it I actually did it wrong and checked my work with my special calculator and it said I was wrong so...let me see.
Yeah, I can't seem to figure out how I got that one wrong. :-/
I'm thinking I have to multiply -8p and 9p since they are like terms
then it becomes 13 = -7 - 3 and then -72 - 3 which becomes -75 then multiply 13 and -75 giving me -975 hmm that seems way too high
This is what I thought: 13 = -8p - 3 + 9p I combine the like terms, which are -8p and 9p by adding 9 to -8 (because you always keep the sign before the number with the number), making the equation 13 = 1p - 3. From there I go to (13 + 3) / 1 Then 16 / 1 And 16 = p
But based on my calculator I am wrong.
But hey, if you have to show your work then if you put that then you'll be at least get 50% credit for trying to solve.
Simplifying 13 = -9p + 13 + 9p Reorder the terms: 13 = 13 + -9p + 9p Combine like terms: -9p + 9p = 0 13 = 13 + 0 13 = 13 Add '-13' to each side of the equation. 13 + -13 = 13 + -13 Combine like terms: 13 + -13 = 0 0 = 13 + -13 Combine like terms: 13 + -13 = 0 0 = 0 Solving 0 = 0 Couldn't find a variable to solve for. This equation is an identity, all real numbers are solutions
that's probably why you're getting two different answers
Wow. I am actually about to leave my computer. Let me try my fastest. Okay, instead of 13 = 13 + 9p + 9p, I would do 13 = 9p + 9p + 13. Anywho, the next step would be combining like terms which would be -9 + 9 = 0p. 13 = 0p + 13. 13 - 13 = 0. 0 / 0 = p = ERROR.
Hm...I don't know. @campbell_st @savannaxx_ @Firejay5 might help. Let me check my special calculator.
yeaa that's why. k thanks for the help
Oh. So you are actually right. P = Always true, or all real numbers.
You are very welcome.
Thanks ! -10 = 5 + z over -5, the answer is actually 45 not -55
Actually no. since it's a negative 55 u would do the opposite and add not subtract.
no it's wrong \[\frac{ z + 5 }{ -5 } = -10\]
you have to multiply -5 to both sides to cancel out the denominator -10 * -5 = 50; then you have z + 5 = 50; substract 5 from both sides and you get z = 45
13 = -8p - 3 + 9p = x = 16
actually the -10 is on the other side. whatever u say
It's better for me to organize my variables
either way you change it's still correct, but it's just switched
I did this stuff in Algebra II you have to get the denominator to cancel out by multiplying
plug -55 back into the regular equation and you will get 10 not -10