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first put equation into y=mx+b then use point slope form y-y1=m(x-x1) m=slope
then the expression will look like y-4+m(x-0)
slope will be -1/5 as it is parallel to the rrquired eqn.so slopes of oth equations wll be same.
u r given a point (0,4) this will be x1 and y1 in the eqn, (y-y1)=slope(x-x1) put the values and try it
How did you figured out the slope was -1/5?
First substitute the value to make y positive: y=-0.2x-3 then use the gradient equation: (y-y1)=m(x-x1) where m is the slope and the point is (x1,y1) and you will get this: y-4=-0.2(x-0) and after simplifying you get: y=-0.2x+4
because the slope on the x value is -1/5 when the coefficient of y is 1
what's the slope of x+15=-5y
you need to get the equation into y = mx+b form first
is it y=1/5x+15
close, but no
umm can you help me with it, y intercept form was a sucky thing for me
start with x+15=-5y and divide both sides by -5 to isolate y
what you have is close, but it's a bit off
hmm how are you getting that?
umm im trying to divide andthen divide both sides by -5
another way to think about it: divide every term by -5 to isolate y
you lost x
it should be -1/5x - 3 = y
it should be y = -1/5x - 3 but you pretty much have it (ignoring the typo)
and whats my next step?
so what is the slope of y = -1/5x - 3
so the slope of any parallel line to this one is also -1/5
since parallel lines have equal slopes
the given point is (0,4) so x = 0 and y = 4 -------------------- we know that m = -1/5, x = 0, y = 4 plug these 3 pieces of info into y = mx + b and solve for b
the slope is negative, so it should be y = -1/5x + 4