anonymous
  • anonymous
Write an equation for a line parallel to x+15=-5y passing through (0,4)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
first put equation into y=mx+b then use point slope form y-y1=m(x-x1) m=slope
anonymous
  • anonymous
0=x1 4=y1
anonymous
  • anonymous
then the expression will look like y-4+m(x-0)

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anonymous
  • anonymous
@twinkieexpress ?
anonymous
  • anonymous
slope will be -1/5 as it is parallel to the rrquired eqn.so slopes of oth equations wll be same.
anonymous
  • anonymous
u r given a point (0,4) this will be x1 and y1 in the eqn, (y-y1)=slope(x-x1) put the values and try it
anonymous
  • anonymous
How did you figured out the slope was -1/5?
anonymous
  • anonymous
First substitute the value to make y positive: y=-0.2x-3 then use the gradient equation: (y-y1)=m(x-x1) where m is the slope and the point is (x1,y1) and you will get this: y-4=-0.2(x-0) and after simplifying you get: y=-0.2x+4
anonymous
  • anonymous
because the slope on the x value is -1/5 when the coefficient of y is 1
anonymous
  • anonymous
@jim_thompson5910 ?
jim_thompson5910
  • jim_thompson5910
what's the slope of x+15=-5y
anonymous
  • anonymous
1
jim_thompson5910
  • jim_thompson5910
you need to get the equation into y = mx+b form first
anonymous
  • anonymous
is it y=1/5x+15
jim_thompson5910
  • jim_thompson5910
close, but no
anonymous
  • anonymous
umm can you help me with it, y intercept form was a sucky thing for me
jim_thompson5910
  • jim_thompson5910
start with x+15=-5y and divide both sides by -5 to isolate y
jim_thompson5910
  • jim_thompson5910
what you have is close, but it's a bit off
anonymous
  • anonymous
umm 7=x-3
jim_thompson5910
  • jim_thompson5910
hmm how are you getting that?
anonymous
  • anonymous
umm im trying to divide andthen divide both sides by -5
jim_thompson5910
  • jim_thompson5910
another way to think about it: divide every term by -5 to isolate y
anonymous
  • anonymous
-1/5-3=y
jim_thompson5910
  • jim_thompson5910
getting closer
anonymous
  • anonymous
ugh
jim_thompson5910
  • jim_thompson5910
you lost x
anonymous
  • anonymous
y=1/5x-3
jim_thompson5910
  • jim_thompson5910
it should be -1/5x - 3 = y
jim_thompson5910
  • jim_thompson5910
much better
jim_thompson5910
  • jim_thompson5910
oh sry
jim_thompson5910
  • jim_thompson5910
it should be y = -1/5x - 3 but you pretty much have it (ignoring the typo)
anonymous
  • anonymous
and whats my next step?
jim_thompson5910
  • jim_thompson5910
so what is the slope of y = -1/5x - 3
anonymous
  • anonymous
-1/5
jim_thompson5910
  • jim_thompson5910
so the slope of any parallel line to this one is also -1/5
jim_thompson5910
  • jim_thompson5910
since parallel lines have equal slopes
jim_thompson5910
  • jim_thompson5910
the given point is (0,4) so x = 0 and y = 4 -------------------- we know that m = -1/5, x = 0, y = 4 plug these 3 pieces of info into y = mx + b and solve for b
anonymous
  • anonymous
y=1/5x+4
jim_thompson5910
  • jim_thompson5910
the slope is negative, so it should be y = -1/5x + 4

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