Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
tell whether each percent change is an increase or decrease. Then find the percent change. Round to the nearest percent. original amount: 45 new amount: 60
 6 months ago
 6 months ago
tell whether each percent change is an increase or decrease. Then find the percent change. Round to the nearest percent. original amount: 45 new amount: 60
 6 months ago
 6 months ago

This Question is Closed

AravindGBest ResponseYou've already chosen the best response.0
What do you think about this question? Any ideas?
 6 months ago

mikaa_toxica13Best ResponseYou've already chosen the best response.1
None. My teacher hasn't taught me this yet. I know it's an increase though.
 6 months ago

HeroBest ResponseYou've already chosen the best response.1
\[\%\Delta = \frac{a  b}{a} \times 100\] \(\%\Delta = \) Percent Change \(a = \) Old Amount \(b = \) New amount
 6 months ago

mikaa_toxica13Best ResponseYou've already chosen the best response.1
Ook Can u use the actual numbers in that ?
 6 months ago

HeroBest ResponseYou've already chosen the best response.1
Yes, that's what you're supposed to do. In this case: \(a = 45\) \(b = 60\)
 6 months ago

mikaa_toxica13Best ResponseYou've already chosen the best response.1
Thank u. It's hard for me to understand this stuff. ok so it would be x = 45−60 ==== ×100 45 45  60 = 15 15 == = 3 45 3(100) = 300
 6 months ago

HeroBest ResponseYou've already chosen the best response.1
\[\frac{15}{45} = \frac{1}{3}\]
 6 months ago

mikaa_toxica13Best ResponseYou've already chosen the best response.1
ok so 1/3(100) = 33
 6 months ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.