Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

ejune420

  • 2 years ago

The graph of f(x)=1/(x^2-c) has a vertical asymptote at x=3. Find c.

  • This Question is Closed
  1. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    This means the function shouldn't exist at x=3. So since you have a fraction and fractions don't exist when the bottom is zero, then when is your bottom 0?

  2. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Or when is x^2-c=0 for x=3.

  3. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Replace x there with 3 and then solve for c.

  4. ejune420
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    so c=9?

  5. myininaya
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Perfect. :) x^2-9 is zero when x=3 which means the function will not exist at x=3 (or even x=-3) but our objective is completed Good job!

  6. ejune420
    • 2 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    Thank you!

  7. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy