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ejune420
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The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
 10 months ago
 10 months ago
ejune420 Group Title
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
 10 months ago
 10 months ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
This means the function shouldn't exist at x=3. So since you have a fraction and fractions don't exist when the bottom is zero, then when is your bottom 0?
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Or when is x^2c=0 for x=3.
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Replace x there with 3 and then solve for c.
 10 months ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Perfect. :) x^29 is zero when x=3 which means the function will not exist at x=3 (or even x=3) but our objective is completed Good job!
 10 months ago

ejune420 Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 10 months ago
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