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ejune420
 one year ago
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
ejune420
 one year ago
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.

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myininaya
 one year ago
Best ResponseYou've already chosen the best response.1This means the function shouldn't exist at x=3. So since you have a fraction and fractions don't exist when the bottom is zero, then when is your bottom 0?

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Or when is x^2c=0 for x=3.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Replace x there with 3 and then solve for c.

myininaya
 one year ago
Best ResponseYou've already chosen the best response.1Perfect. :) x^29 is zero when x=3 which means the function will not exist at x=3 (or even x=3) but our objective is completed Good job!
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