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ejune420
Group Title
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
 one year ago
 one year ago
ejune420 Group Title
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
 one year ago
 one year ago

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myininaya Group TitleBest ResponseYou've already chosen the best response.1
This means the function shouldn't exist at x=3. So since you have a fraction and fractions don't exist when the bottom is zero, then when is your bottom 0?
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Or when is x^2c=0 for x=3.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Replace x there with 3 and then solve for c.
 one year ago

myininaya Group TitleBest ResponseYou've already chosen the best response.1
Perfect. :) x^29 is zero when x=3 which means the function will not exist at x=3 (or even x=3) but our objective is completed Good job!
 one year ago

ejune420 Group TitleBest ResponseYou've already chosen the best response.0
Thank you!
 one year ago
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