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The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
 7 months ago
 7 months ago
The graph of f(x)=1/(x^2c) has a vertical asymptote at x=3. Find c.
 7 months ago
 7 months ago

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myininayaBest ResponseYou've already chosen the best response.1
This means the function shouldn't exist at x=3. So since you have a fraction and fractions don't exist when the bottom is zero, then when is your bottom 0?
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Or when is x^2c=0 for x=3.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Replace x there with 3 and then solve for c.
 7 months ago

myininayaBest ResponseYou've already chosen the best response.1
Perfect. :) x^29 is zero when x=3 which means the function will not exist at x=3 (or even x=3) but our objective is completed Good job!
 7 months ago
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