anonymous
  • anonymous
The graph of f(x)=1/(x^2-c) has a vertical asymptote at x=3. Find c.
Mathematics
chestercat
  • chestercat
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myininaya
  • myininaya
This means the function shouldn't exist at x=3. So since you have a fraction and fractions don't exist when the bottom is zero, then when is your bottom 0?
myininaya
  • myininaya
Or when is x^2-c=0 for x=3.
myininaya
  • myininaya
Replace x there with 3 and then solve for c.

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anonymous
  • anonymous
so c=9?
myininaya
  • myininaya
Perfect. :) x^2-9 is zero when x=3 which means the function will not exist at x=3 (or even x=-3) but our objective is completed Good job!
anonymous
  • anonymous
Thank you!

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