mikaa_toxica13
I have an answer but I'm not sure I did it right. Can anyone check ?



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mikaa_toxica13
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Find the percent error in each estimation. Round to the nearest percent. You estimate that a tree is 45 ft tall. It is actually 58 ft tall.

mikaa_toxica13
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I simply did
58
 45

13%

ganeshie8
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percent error = actual  measured
 x 100
actial

E.ali
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OK !
13 is right but we have :
13 _________x
58________100
Got it ?
we want % of estimate .:)

E.ali
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@ganeshie8 :Realy right :)

mikaa_toxica13
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I did my other questions that way but wasn't sure of the process. Hold on Ill use that equation

ganeshie8
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okiee

E.ali
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OK !:)

mikaa_toxica13
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Ok I got 28

ganeshie8
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close , try again

ganeshie8
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percent error = actual  measured
 x 100
actial
percent error = 58 45
 x 100
58

mikaa_toxica13
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ok this is what I did
x = 45ft  58ft
(100)
45ft
45  58 = 13
 = .28 (100) = 28%
45

ganeshie8
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Yo read the q again,
actual = 58
measured = 45

mikaa_toxica13
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Oh I wrote it backwards

ganeshie8
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yes :

mikaa_toxica13
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ok this is what I did
x = 58ft  45ft
(100)
58ft
58  45 = 13
 = .22 (100) = 22%
58

ganeshie8
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Correct ! good job !!!

mikaa_toxica13
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Thanks ! can u check another for me ?

ganeshie8
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shoot

mikaa_toxica13
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a carpenter estimates the wall is 20ft tall The wall is actually 18ft tall.
x = 18ft  20ft
(100)
18ft
18  20 = 2
 = .11(100) = 11%
18

ganeshie8
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Correct ! looks you got it perfectlyu !!!!
always keep the ACTUAL in the bottom

E.ali
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Very good !

mikaa_toxica13
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Ok thanks !! :)

ganeshie8
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np :)

E.ali
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Do u have any question ?

mikaa_toxica13
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Nope !

E.ali
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k !