A community for students.
Here's the question you clicked on:
 0 viewing
theEric
 one year ago
Hi! Any help with this ODE word problem will be appreciated!
I'll simplify it to the important data:
We are keeping track of the temperature of coffee. Well, we have the temperature at two times and want a third. I would like to be able to conceptualize what's going on, if anyone can help!
7:30am \(200^\circ\text F\)
7:45am \(120^\circ\text F\)
8:00am \(?^\circ\text F\)
The rate of change of heat is a simplified version of Newton's Law of Cooling, that \(\dfrac{dT}{dt}=k(TT_r)\) where \(k\) is a proportionality constant and \(T_r\) is the room temperature (\(70^\circ\text F\)).
theEric
 one year ago
Hi! Any help with this ODE word problem will be appreciated! I'll simplify it to the important data: We are keeping track of the temperature of coffee. Well, we have the temperature at two times and want a third. I would like to be able to conceptualize what's going on, if anyone can help! 7:30am \(200^\circ\text F\) 7:45am \(120^\circ\text F\) 8:00am \(?^\circ\text F\) The rate of change of heat is a simplified version of Newton's Law of Cooling, that \(\dfrac{dT}{dt}=k(TT_r)\) where \(k\) is a proportionality constant and \(T_r\) is the room temperature (\(70^\circ\text F\)).

This Question is Closed

theEric
 one year ago
Best ResponseYou've already chosen the best response.1I figure that I probably need to find out what \(k\) is...

theEric
 one year ago
Best ResponseYou've already chosen the best response.1Can I use \(\Large{\int\limits_{7.5}^{7.75}}\normalsize\dfrac{dT}{dt}dt=\Large{\int\limits_{7.5}^{7.75}}\normalsize k(TT_r)\ dt=200120\)? I'll think on that...

theEric
 one year ago
Best ResponseYou've already chosen the best response.1I haven't done anything like it in class, that I recall.

theEric
 one year ago
Best ResponseYou've already chosen the best response.1But I don't have \(T(t)\) to do integration...

Saeeddiscover
 one year ago
Best ResponseYou've already chosen the best response.0You can say nothing about 8:00 AM here. Because We don't know how the temperature function is changing over time.

theEric
 one year ago
Best ResponseYou've already chosen the best response.1That's what I was thinking as well... But we know the rateofchange function, two points on the \(T\) vs \(t\) curve, which is one solution to the rateofchange function...

theEric
 one year ago
Best ResponseYou've already chosen the best response.1I know that initial value problems require one point...

phi
 one year ago
Best ResponseYou've already chosen the best response.4I think I would solve the equation then use the given data to find the constants \[ \frac{dT}{dt}= k(T T_r) \\ \frac{dT}{(T T_r)}= k \ dt \\\ln(T T_r)= k \ t + C \] where t is time in minutes from 7:30 make each side the exponent of e \[ T T_r= A e^{k\ t} \] now use 7:30 t=0 T= 200 to find A and 7:45 t=15 to find k

theEric
 one year ago
Best ResponseYou've already chosen the best response.1Thank you very much! I'm working on digesting it now.

theEric
 one year ago
Best ResponseYou've already chosen the best response.1\(A\) is an arbitrary constant like \(C\), right?

phi
 one year ago
Best ResponseYou've already chosen the best response.4yes A = e^C we don't care about C per se.

theEric
 one year ago
Best ResponseYou've already chosen the best response.1This is somewhat related, @phi , but do we always need to look at things like \(t=0\) for initial value problems? Or can we use nonzero values for the independent variable?

phi
 one year ago
Best ResponseYou've already chosen the best response.4you can use non zero values of t. But obviously t=0 makes it especially easy to find A

theEric
 one year ago
Best ResponseYou've already chosen the best response.1Right, thank you very much! :)

theEric
 one year ago
Best ResponseYou've already chosen the best response.1In case it is of any viewer's concern: \(A=130^\circ\text F\) \(k=0.0637\ [s^{1}]\) and the coffee will be about \(89.2^\circ\text F\) at 8:00am. :) The problem was about a professor with an 8am class, who never drinks coffee unless it is at \(90^\circ\text F\) or cooler. Good news for him  he can drink the coffee in class! I might show off and solve for the time \(t\) at which he can take his first sip. :P But not until I get the real problems done. Thank you!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.