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sameed1

  • 2 years ago

A particle with the mass of a proton is trapped in a box. The particle falls from the n=3 state to the n=2 state and emits 0.16 meV of energy. What is the size of the box? Please report your answer in nm.

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  1. Migena
    • 2 years ago
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    u need to calculate L^2=2.195*10^-66/3.245*10^-49 after sqrt(6.4*10^-18) and u got the answer :) an u need to convert the meters in nm(1m=10^9nm)

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